我有两个表要连接。
+-----------+-----------+---------+
| row_id | category | val_1 |
+-----------+-----------+---------+
| 1067 | cat1 | 6.5 |
| 2666 | test | 6.5 |
| 2710 | cat1 | 2.1 |
| 2710 | test | 7.1 |
| 2767 | test | 3 |
| 71142 | cat1 | 5 |
| 50666 | other | 6.5 |
| 71142 | other | 1 |
| 345342 | cat1 | 6.5 |
| 345342 | test | 2.8 |
+-----------+-----------+---------+
+-----------+-----------+
| row_id | val_2 |
+-----------+-----------+
| 1067 | 2.0 |
| 2666 | 9 |
| 2701 | 2.2 |
| 2708 | 1 |
| 2709 | 6.5 |
| 2710 | 5.2 |
| 2765 | 6.5 |
| 2766 | 15 |
| 2767 | 8 |
| 71142 | 5 |
| 2783 | 4.5 |
| 50666 | 6.5 |
| 101588 | 9 |
| 101588 | 3 |
| 3452 | 8.0 |
| 23422 | 5 |
| 345342 | 6.5 |
+-----------+-----------+
+-----------+-----------+-----------+------------+
| row_id | val_2 | val_1 | category |
+-----------+-----------+-----------+------------+
| 1067 | 2.0 | 6.5 | cat1 |
| 2666 | 9 | 6.5 | test |
| 2701 | 2.2 | 2.2 | NULL |
| 2708 | 1 | 1 | NULL |
| 2709 | 6.5 | 1 | NULL |
| 2710 | 5.2 | 2.1 | cat1 |
| 2710 | 5.2 | 7.1 | test |
| 2765 | 6.5 | 1 | NULL |
| 2766 | 15 | 1 | NULL |
| 2767 | 8 | 3 | test |
| 71142 | 5 | 5 | cat1 |
| 71142 | 5 | 1 | other |
| 2783 | 4.5 | 1 | NULL |
| 50666 | 6.5 | 6.5 | other |
| 101588 | 9 | 1 | NULL |
| 101588 | 3 | 1 | NULL |
| 3452 | 8.0 | 1 | NULL |
| 23422 | 5 | 1 | NULL |
| 345342 | 6.5 | 6.5 | cat1 |
| 345342 | 6.5 | 2.8 | test |
+-----------+-----------+-----------+------------+
我尝试使用这样的东西:
SELECT TABLE_A.row_id, TABLE_A.category, TABLE_A.val_1, TABLE_B.val_2
FROM TABLE_A
INNER JOIN TABLE_B ON TABLE_B.row_id = TABLE_A.row_id
ORDER BY row_id;
但是,结果仅包含TABLE_A中存在row_id
列的行。
是否可以连接TABLE_A和TABLE_B以生成RESULT_TABLE中显示的结果?
答案 0 :(得分:6)
如果您想要所有结果,则需要外部加入,而不是内部加入。 (Inner只返回匹配的行; outer返回所有行,匹配的行“拼接在一起”)
答案 1 :(得分:5)
尝试外部联接。
SELECT TABLE_A.row_id, TABLE_A.category, TABLE_A.val_1, TABLE_B.val_2
FROM TABLE_B
LEFT OUTER JOIN TABLE_A ON TABLE_B.row_id = TABLE_A.row_id
ORDER BY row_id;
答案 2 :(得分:2)
应该这样做:
SELECT
TABLE_B.row_id row_id,
TABLE_A.category category,
COALESCE(TABLE_A.val_1,1) val_1,
TABLE_B.val_2 val_2
FROM TABLE_A
RIGHT OUTER JOIN TABLE_B
ON TABLE_B.row_id = TABLE_A.row_id
ORDER BY TABLE_B.row_id;
RIGHT OUTER JOIN
从Table_B中提取所有记录,即使它们在Table_A中不存在,并且COALESCE
语句是返回其第一个非NULL参数的函数。在这种情况下,如果Table_A中没有值,它将返回1
,这是您的示例结果列出的所需输出。