我一直试图解决这个问题好几天了,并希望得到一些帮助 -
基本上,我编写了以下Python脚本
import os, sys
# =__=__=__=__=__=__=__ START MAIN =__=__=__=__=__=__=__
if __name__ == '__main__':
# initialize variables
all_files = []
# directory to download data siphon files to
dDir = '/path/to/download/directory/'
# my S3 bucket
s3bucket = "com.mybucket/"
foldername = "test"
# get a list of available feeds
feeds = <huge JSON object with URLs to feeds>
for item in range(feeds['count']):
# ...check if the directory exists, and if not, create the directory...
if not os.path.exists(folderName):
os.makedirs(folderName)
... ... ...
# Loop through all the splits
for s in dsSplits:
... ... ...
location = requestFeedLocation(name, timestamp)
... ... ...
downloadFeed(location[0], folderName, nameNotGZ)
# THIS IS WHERE I AM HAVING PROBLEMS!!!!!!!!!!!
cmd = 's3cmd sync 'dDir+folderName+'/ s3://'+s3bucket+'/'
os.system(cmd)
我的代码中的所有东西都可以工作......当我从命令行直接运行时,一切都按预期运行...但是,当我通过cron执行它时 - 以下不执行(其他所有操作)< / p>
# THIS IS WHERE I AM HAVING PROBLEMS!!!!!!!!!!!
cmd = 's3cmd sync 'dDir+folderName+'/ s3://'+s3bucket+'/'
os.system(cmd)
要回答几个问题,我以root身份运行cron,为root用户配置s3cmd,OS为Ubuntu 12.04,python版本为2.7,所有必需目录都具有读/写权限......
我错过了什么?
答案 0 :(得分:2)
所以我希望命令如下所示..
cmd =&#39; s3cmd sync&#39; + dDir + foldername +&#39; / s3://&#39; + s3bucket +&#39; /&#39;
使用os.system(CMD)
我在这里找到了更多s3cmd同步帮助:http://tecadmin.net/s3cmd-file-sync-with-s3bucket/