Question

我的问题是：

我有3张桌子

Workers_Day，Workers_Night，Total

在workers_Day表中：

ID, Name, Day_one, Day_two

在workers_Night表中：

ID, Name, night_one, night_two

字段将填充1或0（0缺席且1正在工作）

和TOTAL

ID, Name, Total_days_working, Total_nights_Working, Total

我想将表1和表2中的数据插入到表3中。我这样做了一个查询，但它不起作用

insert into total (Id, name, Total_days_working, Total_nights_working, Total)
Select id,name,
IIf([day_one]>0,1,0)+IIf([day_two]>0,1,0) as day_workings,
IIf([night_one]>0,1,0)+IIf([night_two]>0,1,0) as Total_nights_working,
Total_days_working+Total_nights_working AS Total
From Workers_day,Workers_night
Where Workers_day.id = Workers_night.id

条件并非总是如此......

表中有时会有不同的工人但是当ID为“3”的工人“John”在两个表（白天，黑夜）时，问题就开始了

Answer 1

在这一行：

IIf([day_night]>0,1,0)+IIf([day_night]>0,1,0) as Total_nights_working,

列day_night不存在。我认为你的意思是night_one和night_two。

Answer 2

您的代码中有2个错误

正确的是：

insert into total (Id, name, Total_days_working, Total_nights_working, Total)
Select Workers_day.id,Workers_day.name,
IIf([day_one]>0,1,0)+IIf([day_two]>0,1,0) as Total_days_working,
IIf([night_one]>0,1,0)+IIf([night_two]>0,1,0) as Total_nights_working,
Total_days_working+Total_nights_working AS Total
From Workers_day,Workers_night
Where Workers_day.id = Workers_night.id

将两个表中的数据插入一个表中

2 个答案: