多个SELECT语句的正确mySQL语法？

Question

我正在尝试使用一个SELECT语句选择多个列，我尝试了这样并且无效。

mysql> SELECT AVG(salaryoffered) "$ offer" AS "Average Salary", MIN(salaryoffered)
"$ offer" AS "Min Salary", MAX(salaryoffered) "$ offer" AS "Max Salary" FROM
interview;

然而，他们确实工作并单独使用SELECT调出表。像这样：

mysql> SELECT AVG(salaryoffered) "$ offer" AS "Average Salary" 
mysql> SELECT MIN(salaryoffered) "$ offer" AS "Min Salary" 
mysql> SELECT MAX(salaryoffered) "$ offer" AS "Max Salary" 
    -> FROM interview;

知道如何将三个表放在一个命令中吗？ 假设看起来像这样：

+----------------+------------+------------+
| Average Salary | Min Salary | Max Salary |
+----------------+------------+------------+
|      12.080357 |      10.75 |      13.75 |
+----------------+------------+------------+

Answer 1

第一个查询也不行。试试这个。

SELECT AVG(salaryoffered) AS "Average Salary", 
MIN(salaryoffered) AS "Min Salary", 
MAX(salaryoffered) AS "Max Salary" 
FROM interview;

如果你想添加一些文字，请使用concat，比如

SELECT concat(AVG(salaryoffered), "$ offered") AS "Average Salary", 
concat(MIN(salaryoffered), "$ offered") AS "Min Salary", 
concat(MAX(salaryoffered), "$ offered") AS "Max Salary" 
FROM interview;