Question

以下是我要做的是创建一个检查Microsoft Lync是否正在运行的服务。如果它正在运行，那么除了写入事件日志之外什么也不做。如果它没有运行则运行exe然后登录到Lync。我得到的问题是，当运行exe时，它将启动进程，但它实际上从未运行应用程序。我试图看看是否可以使用记事本，但它所做的只是在任务管理器中创建进程但从未打开实际的应用程序。

  Imports System
  Imports System.Data
  Imports System.Timers
  Imports System.Diagnostics
  Imports System.Data.SqlClient
  Imports System.ServiceProcess
  Imports System.Windows.Forms

    Public Class Service1

    Protected Overrides Sub OnStart(ByVal args() As String)
        EventLog.WriteEntry("In Onstart", "starting timer")
           Timer1.Start()
    End Sub



   Protected Overrides Sub OnStop()
   End Sub

   Private Sub Timer1_Elapsed(ByVal sender As System.Object, 
   ByVal e As System.Timers.ElapsedEventArgs) Handles Timer1.Elapsed

       If IsProcessRunning("communicator") Then
       EventLog.WriteEntry("no problem")
       Else
       EventLog.WriteEntry("not running")
       Dim info As New ProcessStartInfo("C:\Program Files (x86)\Microsoft Lync\communicator.exe")
       info.UseShellExecute = False
       info.RedirectStandardError = True
       info.RedirectStandardInput = True
       info.RedirectStandardOutput = True
       info.CreateNoWindow = True
       info.ErrorDialog = False
       info.WindowStyle = ProcessWindowStyle.Hidden

     Dim process__1 As Process = Process.Start(info)

     End If

   End Sub

   Public Function IsProcessRunning(ByVal name As String) As Boolean
      For Each clsProcess As Process In Process.GetProcesses()
        If clsProcess.ProcessName.StartsWith(name) Then
         Return True
      End If
      Next
         Return False
   End Function
End Class

Answer 1

问题来自这样一个事实，即在Windows中（特别是自6.x版本以来）服务在完全隔离的会话和桌面中运行，没有任何用户交互的机会，出于安全考虑，这是设计上的并且不鼓励这样做。您启动的程序实际上会启动，但它会在隐藏的桌面（记事本相同）中启动，没有用户可以看到它。

快速而肮脏的解决方法是在控制面板中将服务标记为交互式，并启动交互式服务检测服务。执行此操作时，当您的服务运行程序时，任务栏中会出现一个窗口，告知有来自服务的消息，以便您可以切换到该并行桌面并实际看到它。这对用户来说非常不方便，并被广泛认为是 BAD PRACTICE 。

真正的解决方案是使程序成为常规应用程序而不是服务，并在Windows中为每个用户运行一些自动启动位置。它不需要具有可见的UI，而是在与您相同的上下文中运行。或者离开服务，但也为了运行第二个程序而将一些应用程序放在与服务通信的用户空间中。在任何情况下，一般规则是永远不要从服务流程进行任何类型的用户交互。

这篇文章解释了问题和一些解决方法http://blogs.technet.com/b/askperf/archive/2007/04/27/application-compatibility-session-0-isolation.aspx

Answer 2

我能够创建一个程序来检测Lync是否正在运行以及它是否未重新启动程序。

Imports System.Diagnostics
Imports Microsoft.Lync
Imports Microsoft.Lync.Model
Imports Microsoft.Lync.Model.Conversation
Imports Microsoft.Lync.Model.Group

Public Class frmCheckLync
Private _lyncClient As LyncClient
Private _contactManager As ContactManager
Private _conversationManager As ConversationManager
Private _self As Self
Private _groups As Dictionary(Of String, Group)
Private _contactSubscriptions As Dictionary(Of String, ContactSubscription)
Public Event StateChanged As EventHandler(Of ClientStateChangedEventArgs)
Public _signIn As IAsyncResult
Public asyncState As Object() = {_lyncClient}
Public clsProcess As Process


Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
    Try

        Timer1.Enabled = True

        AddHandler Timer1.Elapsed, AddressOf Timer1_Tick

        Timer1.Interval = 600

        Timer1.Start()

    Catch ex As Exception

        Diagnostics.EventLog.WriteEntry("This is a test" + ex.Message.ToString, "This is a test")

    End Try
End Sub

Private Sub Timer1_Tick(ByVal sender As Object, ByVal e As System.EventArgs)

    Try

        Timer1.Stop()

        GetClient()


        Try
            CheckClient()
        Catch ex As Exception

        End Try



    Catch ex As Exception




    Finally

        Timer1.Start()

    End Try

End Sub

Public Function IsProcessRunning(ByVal name As String) As Boolean
    For Each Me.clsProcess In Process.GetProcesses()

        If Me.clsProcess.ProcessName.StartsWith(name) Then
            Return True
        End If
    Next
    Return False
End Function

Public Sub GetClient()
    If IsProcessRunning("communicator") = False Then

        Try
            Dim info As New ProcessStartInfo("C:\Program Files\Microsoft Lync\communicator.exe")
            info.UseShellExecute = False
            info.RedirectStandardError = True
            info.RedirectStandardInput = True
            info.RedirectStandardOutput = True
            info.CreateNoWindow = True
            info.ErrorDialog = False
            info.WindowStyle = ProcessWindowStyle.Normal

            Dim process__1 As Process = Process.Start(info)
        Catch ex1 As Exception

        End Try
        Try
            Dim info1 As New ProcessStartInfo("C:\Program Files (x86)\Microsoft Lync\communicator.exe")
            info1.UseShellExecute = False
            info1.RedirectStandardError = True
            info1.RedirectStandardInput = True
            info1.RedirectStandardOutput = True
            info1.CreateNoWindow = True
            info1.ErrorDialog = False
            info1.WindowStyle = ProcessWindowStyle.Normal

            Dim process__2 As Process = Process.Start(info1)
        Catch ex2 As Exception

        End Try
    End If
End Sub
Public Sub CheckClient()
    Try
        _lyncClient = LyncClient.GetClient()
    Catch
        GetClient()
    End Try


    If _lyncClient.State = ClientState.SignedOut Then
        _signIn = _lyncClient.BeginSignIn(Nothing, Nothing, Nothing,
                                          Function(result)
                                              If result.IsCompleted Then
                                                  _lyncClient.EndSignIn(result)
                                                  ' Setup application logic

                                                  ' could not sign in 
                                              Else
                                              End If

                                          End Function, TryCast("Local user signing in", Object))

    End If

End Sub



End Class

VB.net 2010窗口服务运行实际应用程序而不仅仅是进程

2 个答案: