我是JDBC和SQL的新手,我有这个程序但是当我运行它时,我收到以下错误:
java.sql.BatchUpdateException: Field 'stu_id' doesn't have a default value.
我试过操纵线
pst = con.prepareStatement("insert into student(first_name,last_name,address) values (?,?,?)");
在值中添加第4个问号,并在插入到student()中添加stu_id。但是,他们只给出了其他错误。我不知道该怎么办?
package java11;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.SQLException;
import java.sql.Statement;
public class PreparedExample {
public static void main(String[] args) {
Connection con=null;
PreparedStatement pst=null;
try {
Class.forName("com.mysql.jdbc.Driver");
con = DriverManager.getConnection("jdbc:mysql://localhost:3306/world","root","Sree7rama3**");
pst = con.prepareStatement("insert into student(first_name,last_name,address) values (?,?,?)");
for(int i=1;i<=20;i++){
//pst.setInt(1, i);
pst.setString(1, "Hello-"+i);
pst.setString(2, "World-"+i);
pst.setString(3,"HYD-"+i);
pst.addBatch();
}
pst.executeBatch();
System.out.println("Update is successful!");
}catch (SQLException e) {
System.out.println("There are some SQL errors!");
e.printStackTrace();
}catch (ClassNotFoundException e) {
System.out.println("Driver class is not attached to this project!");
e.printStackTrace();
}finally{
try {
pst.close();
} catch (SQLException e) {
e.printStackTrace();
}
try {
con.close();
} catch (SQLException e) {
e.printStackTrace();
}
}
}
}
答案 0 :(得分:0)
看起来当你将stu_id添加到你的声明时,可能是你添加了这行
pst.setInt(1, i);
你有这些行
pst.setString(1, "Hello-"+i);
pst.setString(2, "World-"+i);
pst.setString(3,"HYD-"+i);
所以你要覆盖第一个参数(都是1)。
尝试
pst = con.prepareStatement("insert into student(stu_id,first_name,last_name,address) values (?,?,?,?)");
pst.setInt(1, i);
pst.setString(2, "Hello-"+i);
pst.setString(3, "World-"+i);
pst.setString(4,"HYD-"+i);