我想清理我的old_array并将其拆分为对象数组。所以new_array包含字符串和整数。
这是我的old_array名为$ test_temp_variable,仅在字符串中。
discount_org: [
[
"{"day":"00:00"",
""time":"08:00"",
""discount":"10:00""
],
[
""day":"00:00"",
""time":"14:00"",
""discount":"10:00""
]
这是我想要的输出
discount_org: [
{
day: 0,
time: 8,
discount: 10
},
{
day: 0,
time: 14,
discount: 10
}
但这在PHP中是否可行? 我尝试了几个面向对象的功能,但总是不能正常工作。如果是的话,你能指点一下吗?
我旧数组的var转储
array(7) {
[0]=>
array(3) {
[0]=>
string(13) "{"day":"8:00""
[1]=>
string(14) ""time":"12:00""
[2]=>
string(15) ""discount":"10""
}
[1]=>
array(3) {
[0]=>
string(12) ""day":"8:00""
[1]=>
string(14) ""time":"12:00""
[2]=>
string(15) ""discount":"10""
}
答案 0 :(得分:1)
如果我理解你的话,你必须为你想拥有的每个数组索引创建一个对象,例如:
class Obj {
public $Int;
public $String;
public function setInt($Int) {
$this->Int = $Int
}
public function setString($String) {
$this->String= $String
}
}
然后从中制作一些对象,例如:
$Test = new Obj();
$Test->setInt(3);
并将它们添加到您的数组中,如:
$TestArray[] = $Test;
您现在可以访问它们,如:
$TestArray[0]->Int;
这是你的意思吗?
答案 1 :(得分:0)
也许:
<?php
class MyClass
{
public $property1;
public $property2;
}
$array = array();
$object1 = new MyClass;
$object1->$property1 = 0;
$object1->$property2 = 22;
$object2 = new MyClass;
$object2->$property1 = 11;
$object2->$property2 = 32;
$array[] = $object1; // This adds in order, this would be on $array[0]
$array[] = $object2; // $array[1]
// OR associative way:
$array['Object1'] = $object1;
$array['Object2'] = $object2;
?>
答案 2 :(得分:0)
您可以使用stdClass将数组转换为对象数组:
$arr[] = array('day' => 0,
'time' => 8,
'discount' => 10);
$arr[] = array('day' => 0,
'time' => 14,
'discount' => 10);
$arr[] = array('day' => 1,
'time' => 9,
'discount' => 15);
$discount_org = array();
foreach ($arr as $key => $disc){
$item = new stdClass;
foreach ($disc as $key2 => $val){
$item->$key2 = $val;
}
$discount_org[] = $item;
}
var_dump($discount_org);