我一直试图将这个问题调试好几个小时,并用谷歌搜索它,甚至找不到有同样问题的人。出于某种原因,JSONObject / JSONTokener正在做一些奇怪的事情。
以下代码:
JSONObject jsonObj = (JSONObject) new JSONTokener(sourceJson).nextValue();
Log.d(" ", sourceJson + "\n");
Log.d(" ", jsonObj.toString());
生成此输出:
{
"2012":{
"federal":[[10822,0.15],[42707,0.22],[85414,0.26],[132406,0.29]],
"provincial":{
"AB":[[17282,0.1]],
"BC":[[11354,0.0506],[37013,0.077],[74028,0.105],[84993,0.1229],[103205,0.147]],
"MB":[[8634,0.108],[31000,0.1275],[67000,0.174]],
"NB":[[9203,0.091],[38190,0.121],[76380,0.124],[124178,0.143]],
"NL":[[8237,0.077],[32893,0.125],[65785,0.133]],
"NS":[[8481,0.0879],[29590,0.1495],[59180,0.1667],[93000,0.175],[150000,0.21]],
"NT":[[13280,0.059],[38679,0.086],[77360,0.122],[125771,0.1405]],
"NU":[[12211,0.04],[40721,0.07],[81442,0.09],[132406,0.115]],
"ON":[[9405,0.0505],[39020,0.0915],[78043,0.1116],[500000,0.1216]],
"PE":[[7708,0.098],[31984,0.138],[63969,0.167]],
"QC":[[10925,0.16],[40100,0.2],[80200,0.24]],
"SK":[[14942,0.11],[42065,0.13],[120185,0.15]],
"YT":[[10822,0.0704],[42707,0.0968],[85414,0.1144],[132406,0.1276]]
}
}
}
{"2012":{"provincial":{"ON":[[9405,0.0505],[39020,0.0915],[78043,0.1116],[500000,0.1216]],"AB":[[17282,0.1]],"BC":[[11354,0.0506],[37013,0.077],[74028,0.105],[84993,0.1229],[103205,0.147]],"NL":[[8237,0.077],[32893,0.125],[65785,0.133]],"QC":[[10925,0.16],[40100,0.2],[80200,0.24]],"NU":[[12211,0.04],[40721,0.07],[81442,0.09],[132406,0.115]],"SK":[[14942,0.11],[42065,0.13],[120185,0.15]],"PE":[[7708,0.098],[31984,0.138],[63969,0.167]],"NT":[[13280,0.059],[38679,0.086],[77360,0.122],[125771,0.1405]],"NS":[[8481,0.0879],[29590,0.1495],[59180,0.1667],[93000,0.175],[150000,0.21]],"YT":[[10822,0.0704],[42707,0.0968],[85414,0.1144],[132406,0.1276]],"NB":[[9203,0.091],[38190,0.121],[76380,0.124],[124178,0.143]],"MB":[[8634,0.108],[31000,0.1275],[67000,0.174]]},"federal":[[10822,0.15],[42707,0.22],[85414,0.26],[132406,0.29]]}}
以上格式良好的数据与我用来填充sourceJson
的data.json文件相同,而且很长的行已经神奇地重新排列了省份的顺序(但不是每个省的2D数组中的数据) )。
我也试过了:
JSONObject jsonObj = new JSONObject(sourceJson); // same problem
和
JSONTokener jsonTk = new JSONTokener(sourceJson);
Log.d(" ", jsonTk.toString()); // result = " at character 0 of " + sourceJson;
Log.d(" ", jsonTk.nextValue().toString()); // output same as original problem
我还尝试使用断点来跟踪对nextValue()
的调用,但找不到问题的原因。该行为表明JSONObject(String)构造函数可以调用nextValue(),因为两个方法都提供相同的输出。
所以问题是:有谁知道为什么JSONObject / JSONTokener.nextValue()会以这种方式运行?而且,更重要的是,您是否知道如何在不重新组织的情况下解析JSON数据? (我需要遍历数据,即使数据文件将来发生变化)
非常感谢!
答案 0 :(得分:2)
JSON对象(节点)未订购。它是json格式的定义。在Java中,实现为HashMap的JSON节点和HashMap也没有订购。
如果你真的需要用JSON命令的东西,你需要使用JSON数组。例如:
{
"2012":{
"federal":[[10822,0.15],[42707,0.22],[85414,0.26],[132406,0.29]],
"provincial":{
["code":"AB", data:[[17282,0.1]]],
["code":"BC", data:[[11354,0.0506],[37013,0.077],[74028,0.105],[84993,0.1229],[103205,0.147]]],
["code":"MB", data:[[8634,0.108],[31000,0.1275],[67000,0.174]]]
.
.
.