我试图在积分图中添加一条线,我无法弄明白。我的y值是从0到Inf的数字,而我的x值来自有序因子。
以下是绘图代码,仅显示点:
g = ggplot() +
layer(data = ratesdf, mapping = aes(x = age, y = rates), geom = "point", stat="identity") +
layer(data = ratesdf, mapping = aes(x = age, y = rates), geom = "smooth", stat = "smooth", method = loess)
print(g)
以下是数据框:
rates age
[0,5) 0.00000000 [0,5)
[5,10) 0.00000000 [5,10)
[10,15) 0.00000000 [10,15)
[15,20) 0.02017059 [15,20)
[20,25) 0.32707402 [20,25)
[25,30) 0.54013169 [25,30)
[30,35) 0.71698958 [30,35)
[35,40) 0.81120944 [35,40)
[40,45) 0.87283637 [40,45)
[45,50) 0.91411649 [45,50)
[50,55) 0.91273334 [50,55)
[55,60) 0.95627322 [55,60)
[60,65) 0.92879819 [60,65)
[65,70) 0.98088779 [65,70)
[70,75) 0.90406674 [70,75)
[75,80) 1.00000000 [75,80)
[80,85) 1.00000000 [80,85)
[85,Inf] 1.00000000 [85,Inf]
提前感谢大家!
(哈德利,我保证在我拿到年度生日礼品卡后立即购买你的书:))
答案 0 :(得分:3)
您需要手动指定group = 1,因为默认情况下ggplot2由图上所有分类变量的组合组成。
答案 1 :(得分:0)
我不确定我是否错过了你想要做的事,但基本上想要一个阶梯功能。例如:
rates = c(0.00000000 ,0.00000000 ,0.00000000 ,0.02017059 ,0.32707402, 0.54013169 ,0.71698958 ,0.81120944 ,0.87283637 ,0.91411649 ,0.91273334 ,0.95627322 ,0.92879819 ,0.98088779 ,0.90406674 ,1.00000000 ,1.00000000, 1.00000000 )
age = seq(0, 85, 5)
#ReJig the variables
r2 = sort(rep(rates,2));r2 = r2[1:(length(r2)-1)]
a = sort(rep(age,2));a = a[2:(length(a))]
library(ggplot2)
ggplot() + geom_line(aes(x=a, y=r2))
HTH