我正在使用Flex Tree的iconField属性来动态设置节点应该使用的图标。这适用于叶节点,但对于分支节点,它似乎不尊重我的iconField,而只是显示默认文件夹节点。
这是一个简单的复制品:
<mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute">
<mx:Script>
<![CDATA[
[Embed("assets/icon1.png")]
public var icon1:Class;
[Embed("assets/icon2.png")]
public var icon2:Class;
]]>
</mx:Script>
<mx:XML id="dp">
<node label="Sales" icon="icon1">
<node label="East" icon="icon2"/>
<node label="West" icon="icon2"/>
</node>
</mx:XML>
<mx:Tree dataProvider="{dp}" labelField="@label" iconField="@icon"
width="100%" height="100%" />
</mx:Application>
图标2显示东部和西部节点,但icon1未显示Sales节点。我怎样才能让它发挥作用?
答案 0 :(得分:1)
我认为可以使用iconFunction完成...这看起来像你想要的那样:
http://blog.flexexamples.com/2007/11/15/creating-a-custom-icon-function-on-a-flex-tree-control/
答案 1 :(得分:1)
我明白了。 susichan是正确的iconFunction:
<mx:Script>
<![CDATA[
[Embed("icon1.png")]
public var icon1:Class;
[Embed("icon2.png")]
public var icon2:Class;
[Embed("icon3.png")]
public var icon3:Class;
private function setIcons(item:Object):Class {
var iconClass:Class;
var classType:String = XML(item).attribute("icon");
if(classType!="")
return this[classType];
else
return null;
}
]]>
</mx:Script>
<mx:XML id="dp">
<root>
<node label="Sales" icon="icon1">
<node label="East" icon="icon3"/>
<node label="West" icon="icon3"/>
</node>
<node label="Non-Sales" icon="icon2">
<node label="East" icon="icon3"/>
<node label="West" icon="icon3"/>
</node>
</root>
</mx:XML>
<mx:Tree dataProvider="{dp.node}" labelField="@label" iconField="@icon"
iconFunction="setIcons" showRoot="true"
width="100%" height="100%" />
答案 2 :(得分:0)
几乎! 您需要设置folderOpenIcon和folderClosedIcon,如下所示:
<mx:Tree dataProvider="{dp}" labelField="@label" iconField="@icon"
folderOpenIcon="{icon3}"
folderClosedIcon="{icon4}"
width="100%" height="100%" />