我想将图片上传到网络服务,但是当我上传图片时,只保存图片的名称,而不是图片。
请找到代码和图片供您参考。
- (void) imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info
{
[self dismissModalViewControllerAnimated:YES];
NSData *image = UIImageJPEGRepresentation([info objectForKey:UIImagePickerControllerOriginalImage], 0.1);
NSMutableString *urlString = [[NSMutableString alloc] initWithFormat:@"name=thefile&&filename=recording"];
[urlString appendFormat:@"%@", image];
NSData *postData = [urlString dataUsingEncoding:NSASCIIStringEncoding
allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];
NSString *baseurl = @"http://192.168.2.34/Service1.svc/upload/filename.png";
NSURL *url = [NSURL URLWithString:baseurl];
NSMutableURLRequest *urlRequest = [NSMutableURLRequest requestWithURL:url];
[urlRequest setHTTPMethod: @"POST"];
[urlRequest setValue:postLength forHTTPHeaderField:@"Content-Length"];
[urlRequest setValue:@"application/x-www-form-urlencoded"
forHTTPHeaderField:@"Content-Type"];
[urlRequest setHTTPBody:postData];
NSURLConnection *connection = [NSURLConnection connectionWithRequest:urlRequest delegate:self];
[connection start];
NSLog(@"Started!");
}
上传图片后,图片名称如下所示:
但是当我打开图像时显示为零。
我不确定会出现什么问题。请帮助我。
提前致谢。
答案 0 :(得分:1)
这些行错了:
NSData *image = UIImageJPEGRepresentation([info objectForKey:UIImagePickerControllerOriginalImage], 0.1);
NSMutableString *urlString = [[NSMutableString alloc] initWithFormat:@"name=thefile&&filename=recording"];
[urlString appendFormat:@"%@", image];
NSData *postData = [urlString dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
...
[urlRequest setValue:@"application/x-www-form-urlencoded"
forHTTPHeaderField:@"Content-Type"];
[urlRequest setHTTPBody:postData];
替换为:
NSData *image = UIImageJPEGRepresentation([info objectForKey:UIImagePickerControllerOriginalImage], 0.1);
...
[urlRequest setHTTPBody:image];
你也应该将0.1改为0.8或者其他东西,否则质量会很差。
您还需要确保服务器正确读取数据。这取决于你使用服务器端...在PHP中你就是这样做的:
$data = file_get_contents('php://input');
file_put_contents($data, 'filename.jpg');
答案 1 :(得分:0)
问题在于:
[urlString appendFormat:@"%@", image];
您正在发布数据中链接NSData对象的描述,这是一个错误。 要上传二进制文件,您需要序列化数据或使用multipart / form-data POST请求。
这是两个解决方案:
1)将Base64中的图像NSData转换为此类别(已测试)
https://github.com/l4u/NSData-Base64
然后再做
[urlString appendFormat:@"&image=%@", [image base64EncodedString]];
您需要使用(在PHP中)将服务器上的base64数据转换回来
http://www.php.net/manual/en/function.base64-decode.php
2)实施 File Upload to HTTP server in iphone programming
我希望这会有所帮助。