Question

我在表格中有一个XML列。此列称为UserDef。 Xml看起来像这样：

<UserDefs>
    <UserDef id="EmpNum">002</UserDef>
    <UserDef id="EmpDept">AUT</UserDef>
    <UserDef id="EmpName">XYZ ABC</UserDef>
    <UserDef id="EmpHireDate">2009-11-01T23:59:00-06:00</UserDef>
</UserDefs>

查询应如何返回如下结果：

Column1     Column2 
--------------------
EmpNum      002
EmpDept     AUT
EmpName     XYZ ABC
EmpHireDate 2009-11-01 23:59:00

谢谢。

Answer 1

declare @xml xml
set @xml = '<UserDefs>
            <UserDef id="EmpNum">002</UserDef>
            <UserDef id="EmpDept">AUT</UserDef>
            <UserDef id="EmpName">XYZ ABC</UserDef>
            <UserDef id="EmpHireDate">2009-11-01T23:59:00-06:00</UserDef>
            </UserDefs>'

select R.nref.value('./@id[1]','nvarchar(200)') as Column1,
   R.nref.value('./text()[1]','nvarchar(200)') as Column2
from @xml.nodes('/UserDefs/*') R(nref);

考虑为您的真实数据使用适当的varchar / nvarchar类型长度并且您还需要正确转换日期值

如果我们需要从表中选择：

declare @xml xml
set @xml = '<UserDefs>
        <UserDef id="EmpNum">002</UserDef>
        <UserDef id="EmpDept">AUT</UserDef>
        <UserDef id="EmpName">XYZ ABC</UserDef>
        <UserDef id="EmpHireDate">2009-11-01T23:59:00-06:00</UserDef>
        </UserDefs>'

declare @txml table(UserDef xml)
insert into @txml values (@xml);

select 
a.value('./@id[1]','nvarchar(200)') as Column1,
a.value('./text()[1]','nvarchar(200)') as Column2
from @txml 
CROSS APPLY UserDef.nodes('/UserDefs/*') AS tbl(a)

T-SQL XML检索属性值和相应的元素值

1 个答案: