如何将此sql语句转换为yii格式构建模型?
SELECT DISTINCT agency_id, university_id
FROM `tbl_universityagency` where agency_id=1
像这样我错过了什么? ,
$criteria = new CDbCriteria();
$criteria->distinct=true;
$criteria->condition = "agency_id=".$result->agency_id ;
$modal=Universityagency::model()->find($criteria);
答案 0 :(得分:6)
$criteria = new CDbCriteria();
$criteria->distinct=true;
$criteria->condition = "agency_id=".$result->agency_id ;
$criteria->select = 'id, agency_id, university_id';
$modal=Universityagency::model()->find($criteria);
应该产生查询:
SELECT DISTINCT id,agency_id, university_id FROM `tbl_universityagency` where agency_id=1 LIMIT 1
答案 1 :(得分:4)
您必须使用findAll()
代替find()
。
答案 2 :(得分:1)
快速解决方案!
将以下代码放入模型文件中。
$criteria = new CDbCriteria;
$criteria->distinct = true;
$criteria->condition = "t.C = t.D";
$criteria->group = "t.A";
如果您对此有任何疑问或疑虑,请告诉我们。
谢谢!