Question

id     Bus arrival time
1          6:30
2          7:00
3          9:00
4          10:00
5          15:00
6          16:00

如果一辆公共汽车在6:40到达，那么最近的时间应该是6:30

如果公交车在9:35到达，最近的时间应该是10:00，我需要解决方案作为T-SQL查询

先谢谢，阿尼尔

Answer 1

declare @checkTime time = '6:40'

select top 1 * from schedule
order by ABS(DATEDIFF(Second, @checkTime, busArrivalTime))

SQLFIDDLE

Answer 2

你可以这样做：

DECLARE @TIME TIME = '6:45'


DECLARE @TEMP TABLE(ID int,start time);

insert into @temp values(1, '6:30')
insert into @temp values(1, '7:00')
insert into @temp values(1, '9:00')
insert into @temp values(1, '10:00')
insert into @temp values(1, '15:00')
insert into @temp values(1, '6:30')
insert into @temp values(1, '16:00')


SELECT top(1)start ,ABS(DATEDIFF(MINUTE , @TIME ,START )) as diff
FROM @TEMP
order by diff

如何在SQL Server查询中找到最近的时间？

2 个答案: