我有2张桌子
Products
表:
ID ProductName Category
0 T-Shirt 15
1 Aqua De Gio 12
2 Jacket 15
3 Hot Water 13
Categories
表:
categoryID catagoryName highercategoryID
8 Fragnance 0
99 Clothing 0
15 Armani Clothing 99
12 Armani Fragnance 8
102 Davidoff Fragnance 8
预期结果
ID ProductName Category CategoryTree
0 T-Shirt 15 Clothing > Armani Cloting
1 Aqua De Gio 12 Fragnance > Armani Fragnance
2 Jacket 15 Clothing > Armani Cloting
3 Hot Water 13 Fragnance > Davidoff Fragnance
例如,从产品表中取出T恤
我是SQL查询的新手,这是我第一次尝试
select
x.*,
x.p1 + isnull((' > ' + x.c1), '') + isnull((' > ' + x.c2), '') as CategoryTree
from
(select
RP.categoryid as catid,
RP.catagoryName as p1,
R1.catagoryName as c1,
R2.catagoryName as c2
from
categories as RP
left outer join
categories as R1 on R1.highercategoryid = RP.categoryid
left outer join
categories as R2 on R2.highercategoryid = R1.categoryid
left outer join
categories as R3 on R3.highercategoryid = R2.categoryid
where
RP.highercategoryid != 0 ) x
当我在较高类别中找到0值以及如何在其类别中加入产品时,我不确定如何停止加入,并且是否存在动态方式而不使用大量连接?
答案 0 :(得分:4)
这就是:
With CTE (CatID, CatName, HigherCatID) AS
(
SELECT categoryID, CAST(catagoryName AS VARCHAR(1000)), highercategoryID
FROM CATEGORIES
UNION ALL
SELECT C.categoryID, CAST(CTE.CatName + ' > ' + C.catagoryName AS VARCHAR(1000)), CTE.HigherCatID
FROM CATEGORIES C
INNER JOIN CTE ON C.HigherCategoryID = CTE.CatID
)
SELECT P.ID, P.ProductName, Cte.CatID, CTE.CatName
FROM CTE INNER JOIN PRODUCTS P
ON (CatID = P.Category)
WHERE CTE.HigherCatID=0
你有一个SQLFiddle Here