Question

我收到了这个JSON字符串：

[
{
    "id": 135,
    "date": "2013-08-30 19:00:29",
    "timestamp": "2013-08-30 19:00:29",
    "lat": "54.328274",
    "long": "-2.747215",
    "strap": "annual International Festival of Street Arts",
    "link": "http://dev.website.co.uk//?p=135",
    "title": "Title"
}
]

哪种JSON语法是正确的（在iOS应用程序中正常工作），但是在解析为JSONObject时会捕获错误。爪哇：

public static JSONObject getJSONfromURL(String url){

    //initialize
    InputStream is = null;   
    String result = "";   
    JSONObject jArray = null;

    //http post
    try {

        HttpClient httpclient = new DefaultHttpClient();   
        HttpPost httppost = new HttpPost(url);    
        HttpResponse response = httpclient.execute(httppost);
        HttpEntity entity = response.getEntity();

        is = entity.getContent();    

    } catch (Exception e) {
        Log.e("log_tag", "Error in http connection "+e.toString());   
    }
    //convert response to string

    try {

        BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);  
        StringBuilder sb = new StringBuilder();   
        String line = null;

        while ((line = reader.readLine()) != null) {   
            sb.append(line + "\n");
        }

        is.close();
        result=sb.toString();

    } catch (Exception e) {    
        Log.e("log_tag", "Error converting result "+e.toString());
    }
    //try parse the string to a JSON object

    try {
        Log.d("log_tag", "jresult: " + result + "finish");
        jArray = new JSONObject(result);

    } catch (JSONException e) {
        Log.e("log_tag", "Error parsing data "+e.toString());
    }
    return jArray;
}

JSON中某处有错误吗？

Answer 1

[表示json数组节点

{表示json对象节点

    JSONArray jArray  = new JSONArray(result);
    return jArray;

此外，您可以使用一个试块而不是多个。

Answer 2

这是一个数组，所以你需要做“new JSONArray（）”而不是“new JSONObject（）”。

Answer 3

当json字符串以[开头时，它将被视为JSONArray您需要执行new JSONArray()

JSONObject未正确创建（可能的JSON格式错误？）

3 个答案: