Question

当我尝试使用urllib2发送图像时，会发生UnicodeDecodeError异常。

HTTP帖子正文：

f = open(imagepath, "rb")
binary = f.read()
mimetype, devnull = mimetypes.guess_type(urllib.pathname2url(imagepath))

body = """Content-Length: {size}
Content-Type: {mimetype}

{binary}
""".format(size=os.path.getsize(imagepath),  
           mimetype=mimetype,
           binary=binary)

request = urllib2.Request(url, body, headers)
opener = urllib2.build_opener(urllib2.HTTPSHandler(debuglevel=1))
response = opener.open(request)
print response.read()

追溯：

   response = opener.open(request)
  File "/usr/local/lib/python2.7/urllib2.py", line 404, in open
    response = self._open(req, data)
  File "/usr/local/lib/python2.7/urllib2.py", line 422, in _open
    '_open', req)
  File "/usr/local/lib/python2.7/urllib2.py", line 382, in _call_chain
    result = func(*args)
  File "/usr/local/lib/python2.7/urllib2.py", line 1222, in https_open
    return self.do_open(httplib.HTTPSConnection, req)
  File "/usr/local/lib/python2.7/urllib2.py", line 1181, in do_open
    h.request(req.get_method(), req.get_selector(), req.data, headers)
  File "/usr/local/lib/python2.7/httplib.py", line 973, in request
    self._send_request(method, url, body, headers)
  File "/usr/local/lib/python2.7/httplib.py", line 1007, in _send_request
    self.endheaders(body)
  File "/usr/local/lib/python2.7/httplib.py", line 969, in endheaders
    self._send_output(message_body)
  File "/usr/local/lib/python2.7/httplib.py", line 827, in _send_output
    msg += message_body
  File "/home/usertmp/biogeek/lib/python2.7/encodings/utf_8.py", line 16, in decode
    return codecs.utf_8_decode(input, errors, True)
UnicodeDecodeError: 'utf8' codec can't decode byte 0xff in position 49: invalid start byte

python版本2.7.5

任何人都知道解决方案吗？

Answer 1

您正在尝试发送包含标题和内容的正文。如果要发送内容类型和内容长度，则需要在标题中进行，而不是在正文中：

headers = {'Content-Type': mimetype, 'Content-Length', str(size)}
request = urllib2.Request(url, data=binary, headers=headers)

如果您未设置Content-Length标头，则会自动将其设置为data

的大小

关于你的错误：它发生在行

msg += message_body

如果这两个字符串中的一个是unicode，而另一个str包含\xff，则只会发生此错误，因为在这种情况下，后者将自动同步为unicode sys.getdefaultencoding()。

我的最终猜测是：message_body这是data，str，某处包含\xff。 msg是先前传递给HTTPConnection的内容，即头文件，它们是unicode，因为你在头文件中至少使用了一个密钥的unicode（之前的值转换为str），或者您已从unicode_literals导入__futures__。

使用httplib POST二进制数据会导致Unicode异常

1 个答案: