Question

我想生成一个具有以下结构的nsmutmutable字典：

"user1": {
            "phone Number": "123-123-1234"
            "email": "me@me.com"
            "title": "sales"
            }
"user1": {
            "phone Number": "123-123-1234"
            "email": "me3@me.com"
            "title": "support"
            }
"user2": {
            "phone Number": "123-123-1234"
            "email": "me3@me.com"
            "title": "management"
            }

你们中的任何人都知道我该怎么做？

Answer 1

这样的事情：

    NSMutableDictionary* md = [@{   @"user1" : @{   @"phone Number" : @"123-123-1234",
                                                    @"email" : @"me@me.com",
                                                    @"title" : @"sales" },

                                    @"user2" : @{   @"phone Number" : @"123-123-1234",
                                                    @"email" : @"me2@me.com",
                                                    @"title" : @"support" },

                                    @"user3" : @{   @"phone Number" : @"123-123-1234",
                                                    @"email" : @"me3@me.com",
                                                    @"title" : @"management" }

                                                   } mutableCopy];

或：

    NSMutableDictionary* md2 = [NSMutableDictionary dictionaryWithDictionary:
                                @{  @"user1" : @{   @"phone Number" : @"123-123-1234",
                                                    @"email" : @"me@me.com",
                                                    @"title" : @"sales" },

                                    @"user2" : @{   @"phone Number" : @"123-123-1234",
                                                    @"email" : @"me2@me.com",
                                                    @"title" : @"support" },

                                    @"user3" : @{   @"phone Number" : @"123-123-1234",
                                                    @"email" : @"me3@me.com",
                                                    @"title" : @"management" }
                                } ];

如果您希望每个内部字典都是可变的，您可以应用相同的模式：

    NSMutableDictionary* md3 = [@{  @"user1" : [@{   @"phone Number" : @"123-123-1234",
                                                    @"email" : @"me@me.com",
                                                    @"title" : @"sales" } mutableCopy],

                                    @"user2" : [@{   @"phone Number" : @"123-123-1234",
                                                    @"email" : @"me2@me.com",
                                                    @"title" : @"support" } mutableCopy],

                                    @"user3" : [@{   @"phone Number" : @"123-123-1234",
                                                    @"email" : @"me3@me.com",
                                                    @"title" : @"management" } mutableCopy]

                               } mutableCopy];

Answer 2

你可以定义一个'MyContact'对象。既然你想要一个'结构'，看起来就像你想做的那样，除非我遗漏了一些东西：

@interface MyContact : NSObject {

@property (retain) PhoneNumber;
@property (retain) Email;

- (id) initWithPhone: phone_ Email: _email;
}

...然后

NSMutableDictionary *people = [NSMutableDictionary dictionaryWithObjectsAndKeys: 
   [MyContact initWithPhone: some_number Email: some_email] , @"user1", 
   [MyContact initWithPhone: other_number Email: other_email], @"user2", nil ] ;

如何生成具有多个键和值的NSMutableDictionary

2 个答案: