我有这个MySQL SELECT:
SELECT t.*,
sum(HOUR(TIMEDIFF(STR_TO_DATE(Arbeitsbeginn, '%d.%m.%Y %H:%i:%s'),
STR_TO_DATE(Arbeitsende, '%d.%m.%Y %H:%i:%s')))) AS ARBEITSZEIT,
sum(HOUR(TIMEDIFF(STR_TO_DATE(Projektbeginn, '%d.%m.%Y %H:%i:%s'),
STR_TO_DATE(Projektende, '%d.%m.%Y %H:%i:%s')))) AS Projektzeit
FROM (SELECT DriverName,
Baustelle,
Arbeitsbeginn,
Arbeitsende,
Projektbeginn,
Projektende
FROM (SELECT DRIVERNAME,
GROUP_CONCAT(IF(ACTIONTEXT = 'PB', AREA, NULL)) AS 'Baustelle',
GROUP_CONCAT(IF(ACTIONTEXT = 'Arbeitsbeginn', DATETIME, NULL)) AS 'Arbeitsbeginn',
GROUP_CONCAT(IF(ACTIONTEXT = 'Arbeitsende', DATETIME, NULL)) AS 'Arbeitsende',
GROUP_CONCAT(IF(ACTIONTEXT = 'PB', DATETIME, NULL)) AS 'Projektbeginn',
GROUP_CONCAT(IF(ACTIONTEXT = 'PE', DATETIME, NULL)) AS 'Projektende'
FROM geoImportRoot
GROUP BY DRIVERNAME
) A CROSS JOIN
(SELECT 1 AS n UNION ALL SELECT 2) n
) t
GROUP BY DriverName;
是否可以直接将其插入新表中?
答案 0 :(得分:1)
要从select语句创建 new 表,您可以使用:
它基本上是CREATE TABLE
语句,附加了SELECT
语句。
如果您希望将SELECT
结果插入现有表中,请使用INSERT ... SELECT
语句。