Question

美好的一天。

我正在Spring上编写REST客户端。服务器可以响应发送XML或JSON编组对象。在正常请求/响应的情况下，其工作正常。我的RestTemplate客户端可以解组响应。但是在404错误的情况下，服务器将错误描述符作为XML / JSON发送到响应主体。

我不知道如何解组错误请求正文。

这是我的REST客户端代码：

@Service
public class XsdClientImpl implements InitializingBean, XsdClient {
    private static final Logger LOGGER = LoggerFactory.getLogger(XsdClientImpl.class);
    @Autowired
    @Qualifier("xsdClientRestTemplate")
    private RestTemplate restTemplate;
    private String baseUrl;

    @Override
    public XsdInfoType fetchNamespace(String namespace) throws XsdClientException {
        Map<String, String> vars = Collections.singletonMap("namespace", namespace);
        try {
            return restTemplate.getForObject(baseUrl + "/xsd/get/{namespace}.xml", XsdInfoType.class, vars);
        } catch (final HttpClientErrorException e) {
            // e.getResponseBodyAsByteArray() how to unmarshall it? it can be XML or JSON
            return null;
        }
    }
}

这是Spring config的片段：

<bean id="objectMapper"
      class="org.springframework.http.converter.json.Jackson2ObjectMapperFactoryBean" p:indentOutput="true" p:simpleDateFormat="yyyy-MM-dd'T'HH:mm:ss.SSSZ">
</bean>
<bean class="org.springframework.beans.factory.config.MethodInvokingFactoryBean" p:targetObject-ref="objectMapper" p:targetMethod="registerModule">
    <property name="arguments">
        <list>
            <bean class="com.fasterxml.jackson.datatype.joda.JodaModule"/>
        </list>
    </property>
</bean>

<bean id="stringHttpMessageConverter" class="org.springframework.http.converter.StringHttpMessageConverter"/>
<bean id="jaxb2RootElementHttpMessageConverter" class="org.springframework.http.converter.xml.Jaxb2RootElementHttpMessageConverter"/>
<bean id="mappingJackson2HttpMessageConverter" class="org.springframework.http.converter.json.MappingJackson2HttpMessageConverter">
    <property name="objectMapper" ref="objectMapper"/>
</bean>
<bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer" p:location="classpath:xsd-client.properties"/>

<bean class="org.springframework.web.client.RestTemplate" id="xsdClientRestTemplate">
    <property name="messageConverters">
        <list>
            <ref bean="mappingJackson2HttpMessageConverter"/>
            <ref bean="jaxb2RootElementHttpMessageConverter"/>
        </list>
    </property>
</bean>

注意：在正常情况下，REST服务器发送XsdInfoType编组对象。但是在错误响应对象上有其他类型。

Answer 1

我们可以做RestTemplate的孩子：

HttpMessageConverterExtractor responseExtractor = new HttpMessageConverterExtractor<>(YourErrorType.class, getMessageConverters());
YourErrorType yet = (YourErrorType) responseExtractor.extractData(new ClientHttpResponse(e) {
    // TODO Implement interface. It is very simple.
    // You can get all data from the `e' variable.
    // But I think the Spring has own implementation.
});

RestTemplate unmarshal errorBody

1 个答案: