Question

我正在为mysql创建一个触发器，当用户注册时，旧值将替换为+1作为admin的新值以显示新用户注册。

CREATE TRIGGER `admin_notification_insert`
AFTER INSER ON `userss`
FOR EACH ROW BEGIN
UPDATE `admin-notification` 
SET  NEW.`notification-count` =  (OLD.`notification-count`+1) 
WHERE  `admin-notification`.`notification-id` =1;
END;

我在代码中有错误#1363 - There is no OLD row in on INSERT trigger

查询中可能出现的错误是什么？

Answer 1

通过一些搜索，我能够这样做，所以我自己也回答了这个问题...................

mysource的链接是dev.mysql，我可以解决特定UPDATE test4 SET b4 = b4 + 1 WHERE a4 = NEW.a1;帮助我的例子。我的解决方案的代码如下 -

delimiter |
CREATE TRIGGER `admin_notification_insert`
AFTER INSERT ON `users`
FOR EACH ROW BEGIN
UPDATE `admin-notification` 
SET  `admin-notification`.`notification-count` = `admin-notification`.`notification-count`+ 1 
WHERE  `admin-notification`.`notification-id` = '1';
END;
|
delimiter ;

Answer 2

OLD和NEW指的是触发器所在的表格：userss NOT admin-notification

你可以试试这个：

UPDATE `admin-notification` 
    SET  `notification-count` =  (
        SELECT
            new_nc
        FROM (
            SELECT
                `notification-count`+1 as new_nc
            FROM
                `admin-notification` 
            WHERE
                `admin-notification`.`notification-id` =1
        ) as tmp
    ) 
WHERE  
    `admin-notification`.`notification-id` =1;

mysql查询错误中的触发器

2 个答案: