四舍五入为int C#

时间:2013-06-19 12:15:16

标签: c# wpf precision

我想计算一个BorderControl到添加它的网格的距离,但是以舍入百分比计算。

我使用这种方法:

internal static tPosition GetControlTPosition(Border tempInnerControl, Grid tempOuterGrid)
    {
        tPosition tempTPosition = new tPosition();

        Point tempInnerControlCornerPoint = tempInnerControl.PointToScreen(new Point(0, 0));

        Point tempOuterGridCornerPoint = tempOuterGrid.PointToScreen(new Point(0, 0));

        //
        //Top Left Corner
        //Fist we calculate the Distance of the Top left Corners of both elements
        double distanceLeft = tempInnerControlCornerPoint.X - tempOuterGridCornerPoint.X;
        double distanceTop = tempInnerControlCornerPoint.Y - tempOuterGridCornerPoint.Y;

        //Then we set the percentage of our position accordingly
        tempTPosition.PositionLeft = (int)(((distanceLeft) * 100 / tempOuterGrid.ActualWidth));
        tempTPosition.PositionTop = (int)((distanceTop) * 100 / tempOuterGrid.ActualHeight);

        //
        // Bottom Right Corner
        //Now we calculate the distance of the bottom right corner to the outher grids bottom right corner
        double distanceRight =  (tempOuterGridCornerPoint.X + tempOuterGrid.ActualWidth) - (tempInnerControlCornerPoint.X + tempInnerControl.ActualWidth);
        double distanceBottom = (tempOuterGridCornerPoint.Y + tempOuterGrid.ActualHeight) - (tempInnerControlCornerPoint.Y + tempInnerControl.ActualHeight);

        tempTPosition.PositionRight = (int)((distanceRight)*100/tempOuterGrid.ActualWidth);
        tempTPosition.PositionBottom = (int)((distanceBottom) * 100 / tempOuterGrid.ActualHeight);

        return tempTPosition;
    }

我的问题是BorderControl一直在变大,这意味着百分比低的问题,我想这是因为我失去了精确度。我怎么能避免这个?

出于各种原因,我需要将数字作为int。

tPosition只是左侧,上方,右侧,底部为整体

1 个答案:

答案 0 :(得分:1)

你很可能在找到tempTPosition时失去你的精确度,而不是像你使用int一样使用double,这会将值四舍五入为整数

尝试使用双打

//Then we set the percentage of our position accordingly
    tempTPosition.PositionLeft = (double)(((distanceLeft) * 100 / tempOuterGrid.ActualWidth));
    tempTPosition.PositionTop = (double)((distanceTop) * 100 / tempOuterGrid.ActualHeight);

请记住也要为PositionRight& PositionBottom