Question

我调用upload函数并返回一个变量。当我var_dump($x)时，它会显示以下内容：

{"files":[{"name":"1004046_469695273124093_104592888_n_1_28860.jpg","size":0,"type":"image\/jpeg","error":"abort","delete_url":"http:\/\/www.xxx.com\/upload\/uploader\/server\/php\/?file=1004046_469695273124093_104592888_n_1_28860.jpg","delete_type":"DELETE"}]}array(1) {
["files"]=>
    array(1) {
     [0]=> object(stdClass)#24 (6) {
     ["name"]=> string(47) "1004046_469695273124093_104592888_n_1_28860.jpg"
     ["size"]=> int(0)
     ["type"]=> string(10) "image/jpeg"
     ["error"]=> string(5) "abort"
     ["delete_url"]=> string(104) "http://www.xxx.com/upload/uploader/server/php/?file=1004046_469695273124093_104592888_n_1_28860.jpg"
     ["delete_type"]=> string(6) "DELETE"
    }
 }
}

我尝试var_dump(json_decode($x))，结果为NULL。

我的问题是如何从这个???

获取值名称

尝试了这两个：

echo $x->files[0]->name;
echo " ********************** ";
echo $x['files'][0]->name;
echo " ********************** ";

，结果是

{"files":[{"name":"1004046_469695273124093_104592888_n_1_14299.jpg","size":78289,"type":"image\/jpeg","url":"http:\/\/www.xxx.com\/upload\/uploader\/server\/php\/files\/1004046_469695273124093_104592888_n_1_14299.jpg","thumbnail_url":"http:\/\/www.xxx.com\/upload\/uploader\/server\/php\/files\/thumbnail\/1004046_469695273124093_104592888_n_1_14299.jpg","delete_url":"http:\/\/www.xxx.com\/upload\/uploader\/server\/php\/?file=1004046_469695273124093_104592888_n_1_14299.jpg","delete_type":"DELETE"}]}{"files":[{"name":"1004046_469695273124093_104592888_n_1_12920.jpg","size":0,"type":"image\/jpeg","error":"abort","delete_url":"http:\/\/www.xxx.com\/upload\/uploader\/server\/php\/?file=1004046_469695273124093_104592888_n_1_12920.jpg","delete_type":"DELETE"}]}
********************** 
{"files":[{"name":"1004046_469695273124093_104592888_n_1_15697.jpg","size":0,"type":"image\/jpeg","error":"abort","delete_url":"http:\/\/www.xxx.com\/upload\/uploader\/server\/php\/?file=1004046_469695273124093_104592888_n_1_15697.jpg","delete_type":"DELETE"}]}1004046_469695273124093_104592888_n_1_15697.jpg
**********************

Answer 1

你试过了吗？

$name_val = $x->files[0]->name;

Answer 2

$_FILES['files']['error'];
$_FILES['files']['name'];

我如何从数组/对象获取值

2 个答案: