Question

我正在尝试创建一个查询，该查询将在整个24小时工作日累计轮班员工人数。因此，当用户采取从2013-06-17 10:00:00开始到14:00:00结束的班次时，我希望用户在5个单元格中“计数”

2013-06-17 10 : +1 here
2013-06-17 11 : +1 here
2013-06-17 12 : +1 here
2013-06-17 13 : +1 here
2013-06-17 14 : +1 here

这应该最终为我提供24小时范围，向我显示在特定时间内有多少员工在工作。

我使用了3张桌子。

teamslots
---------
id
startdate
starttime
endtime

teamslot_schedule
-----------------
id
slotid (joins to is in teamslots)
userid

shifthours
----------
thehour

在shifthours中，我有24条记录 - 0 - 23我需要的每小时一条记录。

然后我尝试在HOUR（teamslots.starttime）AND GROUP BY startdate上休息，小时但没有真正的运气。

这是我的查询（当前返回24行的thehour，null，null）

SELECT a.thehour,b.startdate,b.taken FROM shifthours a LEFT JOIN (SELECT startdate,starttime,endtime,count(DISTINCT b.id) as taken FROM teamslots a
LEFT JOIN teamslot_schedule b ON a.id=b.slotid) b ON a.thehour=HOUR(b.starttime)
GROUP BY b.startdate,a.thehour;

有谁能请我帮助我 - 指出我正确的方向？

Answer 1

简短的想法。在相关日期提出一系列小时数（假设查询提前知道日期），并在开始和结束时间之间进行联接。

像这样： -

SELECT DATE_ADD('2013/06/17', INTERVAL thehour HOUR), COUNT(teamslot_schedule.id)
FROM shifthours
LEFT OUTER JOIN teamslots
ON DATE_ADD('2013/06/17', INTERVAL thehour HOUR) BETWEEN starttime AND starttime AND endtime
LEFT OUTER JOIN teamslot_schedule
ON teamslots.id = teamslot_schedule.slotid
GROUP BY DATE_ADD('2013/06/17', INTERVAL thehour HOUR)

请注意，这不会直接起作用，因为我不确定您的starttime / endtime与startdate的关系。

Answer 2

以下查询将包含无人工作时的小时数：

SELECT
    DATE_FORMAT(d.startdate + INTERVAL s.thehour HOUR, '%Y-%m-%d %H') AS date,
    COUNT(DISTINCT ts.userid) AS users
FROM
    shifthours s
JOIN
    (SELECT DISTINCT startdate FROM teamslots) d
LEFT JOIN
    teamslots t ON t.startdate = d.startdate AND
        s.thehour BETWEEN HOUR(t.starttime) AND HOUR(t.endtime)
LEFT JOIN
    teamslot_schedule ts ON ts.slotid = t.id
GROUP BY
    d.startdate,
    s.thehour
ORDER BY
    d.startdate + INTERVAL s.thehour HOUR;

有关工作示例，请参阅http://sqlfiddle.com/#!2/4a716/13

以下查询仅包含有人工作时的行：

SELECT
    DATE_FORMAT(t.startdate + INTERVAL s.thehour HOUR, '%Y-%m-%d %H') AS date,
    COUNT(DISTINCT ts.userid) AS users
FROM
    shifthours s
INNER JOIN
    teamslots t ON s.thehour BETWEEN HOUR(t.starttime) AND HOUR(t.endtime)
LEFT JOIN
    teamslot_schedule ts ON ts.slotid = t.id
GROUP BY
    t.startdate,
    s.thehour
ORDER BY
    t.startdate + INTERVAL s.thehour HOUR;

有关工作示例，请参阅http://sqlfiddle.com/#!2/4a716/15

mysql - 查询以查找每小时每天累计的SUM

2 个答案: