Question

我有一个像这样的NSString：

NSString *word = @"119,111,114,100"

所以，我想要做的是将这个NSString转换为单词

所以问题是，我可以通过哪种方式将字符串转换为单词？

Answer 1

// I have added some values to your sample input :-)
NSString *word = @"119,111,114,100,32,240,159,145,141";

// Separate components into array:
NSArray *array = [word componentsSeparatedByString:@","];

// Create NSData containing the bytes:
NSMutableData *data = [[NSMutableData alloc] initWithLength:[array count]];
uint8_t *bytes = [data mutableBytes];
for (NSUInteger i = 0; i < [array count]; i++) {
    bytes[i] = [array[i] intValue];
}

// Convert to NSString (interpreting the bytes as UTF-8):
NSString *str = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];

NSLog(@"%@", str);

输出：

word

Answer 2

试试这个：

NSString *word = @"119,111,114,100";
NSArray *array=[word componentsSeparatedByString:@","];
for (NSString *string in array) {
   char character=[string integerValue];
    NSLog(@"%c",character);    
}

输出：

w
o
r
d

Answer 3

libicu它是一个UTF8库，它支持从here所述的字节数组转换。

问题是，它提供Java，C或C ++ API，而不是obj-c。

如何转换字符串utf-8？

3 个答案: