Question

我的代码中有以下内容，我无法完成代码工作的后半部分。为了更准确地说明我的问题，我按照我想要的方式工作，直到我点击OneClick。完成后，我得到另一个表单（form2），其中TwoClick提交按钮动态填充。这个问题来了。当我点击按钮TwoClick时，整个'form2'消失了。有人可以告诉我哪里出错了吗？

感谢。

    <?php session_start(); ?>
<DOCTYPE html>
<html>
<head><title></title>
</head>
<body>
<div id="One">
    <form name="form1" method="post" action="#">
        <?php echo "<input type='text' name='txt1' id='txt1'>"; // This text box is dynamically populated ?>
              <input type="submit" name="sendone" id="sendone" value="OneClick">
    </form>
</div>

<div id="two">


            <?php
            if(isset($_POST['sendone']))
            {   if($_POST['txt1'] == '')
                {echo 'txt1 is empty!'; return;} else {$_SESSION['txt1'] = $_POST['txt1'];}

                        if(isset($_SESSION['txt1'])) 
                        echo $_SESSION['txt1']; 
                        echo "<form name='form2' method='post' action='#'><table border='1'><tr><td>form 2 is here!<br></td></tr><tr><td><input type='text' name='txt123' id='txt123'></td></tr> <tr><td><input type='submit' name='sendtwo' id='sendtwo' value='TwoClick'></td></tr></table></form>";



            }   
                        if(isset($_POST['sendtwo']))
                        if(isset($_POST['sendtwo'])) 
                        {
                            if($_POST['txt123'] == '')
                            {echo "Text box is empty..."; return;}
                        }               
                        ?>

        </div>
    </body>
</html>

Answer 1

Session_start()（在脚本的开头）。
由于您的逻辑，Sendtwo表单消失 - 当您提交Sendtwo时，$_POST['sendone'] 未设置，因此不会被回显。要解决这个问题，您可以将第一个条件更改为：

if (isset($_POST['sendone']) || isset($_POST['sendtwo']))

Answer 2

尝试放

if(isset($_POST['sendtwo']))
         if(isset($_POST['sendtwo'])) 
         {
             if($_POST['txt123'] == '')
                      {echo "Text box is empty..."; return;}
         }

在最后。我的意思是在最后}

之后

Answer 3

尝试此示例并阅读代码注释。虽然我真的不清楚你的尝试是什么，所以我只是把代码移植到我认为你尝试的todo，有更好的方法来处理表格。另外你应该考虑你的表单值键，txt1和txt123没有帮助，也不要从表单中解释你想要的变量类型。也许是它的兴趣。

<?php 
session_start();
if($_SERVER['REQUEST_METHOD']=='POST'){
    $form = null;
    //Handle form 1
    if(isset($_POST['sendone'])){
        //reset session vars if new request
        unset($_SESSION['txt1']);
        unset($_SESSION['txt123']);

        //validate txt1
        if(!empty($_POST['txt1'])){
            //set into session
            $_SESSION['txt1'] = $_POST['txt1'];
            //or you could put the value in a <input type="hidden" name="txt1" value="'.htmlspecialchars($_POST['txt1']).'"/>

            $form = "
    <form name='form2' method='post' action=''>
        <table border='1'>
        <tr>
            <td>form 2 is here!<br></td>
        </tr>
        <tr>
            <td><input type='text' name='txt123' id='txt123'></td>
        </tr>
        <tr>
            <td><input type='submit' name='sendtwo' id='sendtwo' value='TwoClick'></td>
        </tr>
        </table>
    </form>";
        } else {
            $error['txt1'] = 'txt1 is empty!';
        }
    }

    //do second form
    if(isset($_POST['sendtwo'])){
        //validate
        if(!empty($_POST['txt123'])){
            //set session
            $_SESSION['txt123'] = $_POST['txt123'];
        }else{
            $error['txt123'] = 'txt2 is empty!';
        }
    }

    //check then do something with both form values
    if(empty($error) && isset($_SESSION['txt1']) && isset($_SESSION['txt123'])){
        $form = "Both txt1=".htmlspecialchars($_SESSION['txt1'])." and txt123=".htmlspecialchars($_SESSION['txt123'])." was set into session";
    }

}
?>
<DOCTYPE html>
<html>
<head><title></title>
</head>
<body>

    <div id="One">
        <form name="form1" method="post" action="">
            <input type='text' name='txt1' id='txt1'> 
            <input type="submit" name="sendone" id="sendone" value="OneClick"> 
            <?php echo isset($error['txt1'])?$error['txt1']:null;?>
        </form>
    </div>

    <div id="two">
      <?php echo isset($form)?$form:null;?>
    </div>
    </body>
</html>

Answer 4

试试这个

<?php
    session_start();
    function putForm2(){
    $myForm = "<form name='form2' method='post' action='#'><table border='1'><tr><td>form 2 is here!<br></td></tr><tr><td><input type='text' name='txt123' id='txt123'></td></tr> <tr><td><input type='submit' name='sendtwo' id='sendtwo' value='TwoClick'></td></tr></table></form>";
    return $myForm;
    }
?><!DOCTYPE html>
    <html>
<head><title></title>
</head>
<body>
<div id="One">
    <form name="form1" method="post" action="#">
        <?php echo "<input type='text' name='txt1' id='txt1'>"; // This text box is dynamically populated ?>
              <input type="submit" name="sendone" id="sendone" value="OneClick">
    </form>
</div>

<div id="two">


            <?php
            if(isset($_POST['sendone']))
            {   if($_POST['txt1'] == '')
                {echo 'txt1 is empty!'; return;} else {$_SESSION['txt1'] = $_POST['txt1'];}

                        if(isset($_SESSION['txt1'])) 
                        echo $_SESSION['txt1']; 
                        echo putForm2();



            }   
                        if(isset($_POST['sendtwo']))
                        if(isset($_POST['sendtwo'])) 
                        {
                            if($_POST['txt123'] == '')
                            {
                                echo putForm2();
                                echo "Text box is empty..."; return;
                            }
                        }               
                        ?>

        </div>
    </body>
</html>

表单在PHP中提交时消失

4 个答案: