Question

下面给出的是我在做完

后得到的json数组

$data = json_decode($response);

foreach($data[songs] as $key => $value) {
 echo $value['title']; 
}

我收到一条错误，说这是非法的字符串偏移'歌曲'。有人可以帮忙吗？

{
   "response":{
      "status":{
         "version":"4.2",
         "code":0,
         "message":"Success"
      },
      "start":0,
      "total":169,
      "songs":[
         {
            "id":"SOVZDWG13EDE8AA5F6",
            "title":"Live And Let Die (Professional Backing Track)"
         },
         {
            "id":"SOVZQDT1373E96845D",
            "title":"Cival War"
         },
         {
            "id":"SOIHVBA1373E967FC7",
            "title":"Free Fallin'"
         },
         {
            "id":"SOHTILC137377A4D5A",
            "title":"PARADISE CITY (1989 Radio Edit)\/(CONTENT!)"
         },
         {
            "id":"SOTHTHM137376FDC30",
            "title":"IT'S SO EASY (CC Cleaner Edit)\/(LYRICS!)\/(CONTENT!)"
         },
         {
            "id":"SOSGUMG137392B086C",
            "title":"MR. BROWNSTONE (CC Clean)"
         },
         {
            "id":"SOAIMVY13739563B7F",
            "title":"NOVEMBER RAIN (Long Edit)"
         },
         {
            "id":"SOHTFWB13732F1645D",
            "title":"MOVE TO THE CITY (Live)\/(CC Clean)\/(CONTENT!)"
         },
         {
            "id":"SOINGWZ137337DD251",
            "title":"CIVIL WAR (CONTENT!)"
         },
         {
            "id":"SOJMUVZ136F21B42BC",
            "title":"Neurobomb"
         },
         {
            "id":"SOXPBNG136749B5A8B",
            "title":"SWEET CHILD O' MINE (Edit\/Remix)"
         },
         {
            "id":"SOCQGYZ1366D7B44B0",
            "title":"MADAGASCAR (CC Clean Edit)"
         },
         {
            "id":"SOXHMOW1366D7B84F6",
            "title":"RIAD N' THE BEDOUINS (CC Clean)"
         },
         {
            "id":"SOFCXWC1366DBED3DA",
            "title":"Nighttrain (Live)"
         },
         {
            "id":"SORXNZT1366E397CEC",
            "title":"DUST N' BONES (CC Clean)"
         }
      ]
   }
}

Answer 1

简单的json_decode($jsonstring)将返回stdClass对象和数组的混合。字符串键是对象属性，JSON数组是从索引0开始的PHP数组。

使用json_decode($jsonstring, true)仅获取包含字符串键的数组。

Answer 2

只需执行var_dump（$ data），你的错误就会很明显。

Answer 3

试试这个：

foreach($data->response->songs as $song) {
    print_r($song);
}

你有两个问题。一个您没有访问response属性的，并且您没有将json_decode()的结果视为对象。

Answer 4

我不确定，但我猜你不能先访问数据['songs']而不先把'响应'扔出去

用PHP解析Json

4 个答案: