从变量中删除括号和尾随空格

Question

删除括号和任何（但仅限于）尾随空格的正则表达式是什么？

示例："Hello [world] - what is this?"会转换为"Hello - what is this?"。

Answer 1

使用以下正则表达式。它将删除括号及其尾随空格。

/(\s\s)*(\s(?=\[.*?\]\s))*\[.*?\](\s\s)*/g

用法：

var testStr = "Hello [world] - what is this?";
console.log(testStr.replace(/(\s\s)*(\s(?=\[.*?\]\s))*\[.*?\](\s\s)*/g, ""));

输入/输出：

Input: Hello [world] - what is this?            Output: Hello - what is this?
Input: Hello [world] - what  is  this?          Output: Hello - what  is  this?
Input: Hello [world] - what is     this?        Output: Hello - what is     this?
Input: Hello      [world] - what is this?       Output: Hello - what is this?
Input: Hello      [world]     - what is this?   Output: Hello - what is this?
Input: Hello [world]       - what is this?      Output: Hello - what is this?
Input: Hello [world]- what is this?             Output: Hello - what is this?
Input: Hello       [world]- what is this?       Output: Hello - what is this?
Input: Hello[world] - what is this?             Output: Hello - what is this?
Input: Hello[world]       - what is this?       Output: Hello - what is this?
Input: Hello[world]- what is this?              Output: Hello- what is this? 

Answer 2

你可以让表达式在括号内的东西和尾随的空格之间交替：

str.replace(/\[[^\]]*\]|\s+$/g, '')

/g修饰符用于匹配所有匹配项，而不是仅匹配第一个（默认值）。

<强>更新

如果[hello]前面有空格，则该空格不会被移除，您需要另外.replace()而不是替换：

str.replace(/\[[^\]]*\]/g, '').replace(/\s+$/, '');

Answer 3

你可以这样做：

var result = mystring.replace(/^\s*\[[^]]+]\s*|\s*\[[^]]+]\s*$|(\s)\s*\[[^]]+]\s*/g, '$1');

Answer 4

str.replace(/\[.+?\]\s*/g,'');