Question

如何通过使用jquery ajax调用传递id来删除行这是delete.php

<?php

require_once('DB.class.php');
$dbconnect = new DB('schoollife', 'root', '');

$id=$_GET['chapter_id'];

$del="DELETE FROM sl_chapter WHERE chapter_id=".$id ;
$result=mysql_query($del);

// if successfully deleted
if($result){
echo "<font color='red'>record deleted successful</font>";
//echo "<BR>";
//echo "<a href='delete.php'>Back to main page</a>";
}
else {
echo "<br/>";
die('Error: ' . mysql_error());
} 

?>

这是chapter.html

<script>
 $(document).on('click','.delbutton',function(){ 
        var del_id = element.attr("id");
        var info = 'id=' + del_id;
        if(confirm("Are you sure you want to delete!"))
        {
        $.ajax({
        type: "json",
        url: "delete.php",
        //data: info,
        success: function(){
        }
        });
        $(this).parents(".record").animate({ backgroundColor: "#fbc7c7" }, "fast")
        .animate({ opacity: "hide" }, "slow");
        }
        return false;

        });
            </script>

如何通过使用jquery ajax调用传递id来删除行我认为删除查询错了..

Answer 1

你几乎就在那里，你需要将要删除的id传递给delete.php

chapter.html：

<script>
 $(document).on('click','.delbutton',function(){ 
        var del_id = element.attr("id");
        if(confirm("Are you sure you want to delete!"))
        {
        $.ajax({
        type: "POST", //changed
        url: "delete.php",
        data: 'id=' + del_id, // changed
        success: function(){
        }
        });
        $(this).parents(".record").animate({ backgroundColor: "#fbc7c7" }, "fast")
        .animate({ opacity: "hide" }, "slow");
        }
        return false;

        });
            </script>

delete.php：

require_once('DB.class.php');
$dbconnect = new DB('schoollife', 'root', '');

$id=$_POST['id']; //changed

$del="DELETE FROM sl_chapter WHERE chapter_id=".$id ;
$result=mysql_query($del);

// if successfully deleted
if($result){
echo "<font color='red'>record deleted successful</font>";
//echo "<BR>";
//echo "<a href='delete.php'>Back to main page</a>";
}
else {
echo "<br/>";
die('Error: ' . mysql_error());
} 

?>

Answer 2

您在jquery中发送JSON类型，但type应该是POST或GET

$.ajax({
    type: "GET", // should be GET or POST not JSON
    url: "delete.php",
    data: info,
    success: function(){
    }
});

另请在delete.php

中进行更改

$id=$_GET['chapter_id'];

到

$id=$_GET['id'];

More info

Answer 3

好的，一些修复：

您正在发送JSON而不是GET
我假设您只想在删除后执行动画，因此请将动画放在success内。（如果没有，请忽略这一点。）
请勿发表评论data

将id替换为chapter_id变量

中的info

$(document).on('click','.delbutton',function(){ 
var del_id = element.attr("id");
var info = 'chapter_id=' + del_id;

if(confirm("Are you sure you want to delete!"))
{
    $.ajax({
    type: "get",
    url: "delete.php",
    data: info,
    success: function(){
        $(this).parents(".record").animate({ backgroundColor: "#fbc7c7" }, "fast").animate({ opacity: "hide" }, "slow");
    }
    });
}
return false;
});

jquery ajax调用在mysql中删除一行

3 个答案: