vb.net中整数的datagridview单元格验证

时间:2013-06-07 07:32:11

标签: vb.net datagridview

如何使验证仅通过正整数?我有一个列可以触发错误,如果它是非整数但是用户仍然可以将负整数键入该列的单元格。

3 个答案:

答案 0 :(得分:0)

如何使用javascript代码?添加此js事件

onkeypress=""return allowOnlyNumber(event);

然后您需要的只是

function allowOnlyNumber(evt)
{
  var charCode = (evt.which) ? evt.which : event.keyCode
  if (charCode > 31 && (charCode < 48 || charCode > 57))
    return false;
  return true;
}

否则您可以使用AjaxControlToolkit中的FilteredTextBoxExtender作为

<asp:TextBox ID="txtbox1" runat="server"></asp:TextBox>
            <cc1:FilteredTextBoxExtender id="ftbe" runat="server" targetcontrolid="txtbox1"
                  filtertype="Numbers" validchars="0123456987" />

答案 1 :(得分:0)

Nvm我发现它我将稍后更新链接列index =表示当前单元格是否在该列中使用以下代码验证它对不起麻烦的人。链接位于Here

           If grdDataGrid.CurrentCell.ColumnIndex = 4 Then
           If Not Integer.TryParse(e.FormattedValue.ToString(), newInteger) _
            OrElse newInteger < 0 Then

            e.Cancel = True
            Me.grdDataGrid.Rows(e.RowIndex).ErrorText = "the value must be a non-negative         integer"
            MsgBox("You must enter a positive number")
        End If
     End If

答案 2 :(得分:0)

在您的Datagridview EditingControlShowing事件中尝试...

Private Sub DataGridView1_EditingControlShowing(ByVal sender As Object, ByVal e As System.Windows.Forms.DataGridViewEditingControlShowingEventArgs) Handles DataGridView1.EditingControlShowing
    Try

        If UCase(sCellName) = "QUANTITY"

             AddHandler e.Control.KeyPress, AddressOf TextNumberKeypress

        End If

    Catch ex As Exception
        '... 
    End Try
End Sub


Sub TextNumberKeypress(ByVal sender As Object, ByVal e As System.Windows.Forms.KeyPressEventArgs)
    Dim k As Byte = Asc(e.KeyChar)

    If Not IsNumSimple(k) Then
        e.Handled = True
        If Not (k = 8 Or k = 13 Or k = 1 Or k = 3 Or k = 22) Then e.Handled = True
    End If
End Sub