Question

我有一个包含2个字段的表：

Day_col   | Value_col
2013-06-06  1
2013-06-05  2
2013-06-04  3
2013-06-03  4
2013-06-02  5

我想创建一个sql（sum（Value_col）3天后 - 如果有3天或更多将是总和，如果少于3天不总和）然后收到这样的结果：

Day_col   | total
2013-06-06  9     <- total after '2013-06-06' 3 days are 5,4,3 is 9
2013-06-05  12    <- total after '2013-06-05' 3 days are 4,3,2 is 12
2013-06-04  --    <- total after '2013-06-04' 2 days don't sum
2013-06-03  --    <- total after '2013-06-03' 1 days don't sum
2013-06-02  --    <- total after '2013-06-02' 0 days don't sum

请帮助

Answer 1

SELECT
    Day_col,
    IF (
        (SELECT COUNT(Value_col) FROM myTable AS subT WHERE subT.Day_col < t.Day_col) >= 3,
        (SELECT SUM(Value_col) FROM myTable AS subT WHERE subT.Day_col < t.Day_col and DATE_ADD(subT.Day_col, INTERVAL 3 DAY) >= t.Day_col),
        '--'
    ) AS total
FROM
    myTable t

Answer 2

CREATE TABLE foo
    (`Day_col` varchar(10), `Value_col` int)
;

INSERT INTO foo
    (`Day_col`, `Value_col`)
VALUES
    ('2013-06-06', 1),
    ('2013-06-05', 2),
    ('2013-06-04', 3),
    ('2013-06-03', 4),
    ('2013-06-02', 5)
;

SELECT
Day_col,
IF (
(SELECT COUNT(Value_col) FROM foo AS sf WHERE sf.Day_col < f.Day_col) >= 3,
(SELECT SUM(Value_col) FROM foo AS sf WHERE sf.Day_col >= f.Day_col - INTERVAL 3 DAY and sf.Day_col < f.Day_col),
'--'
) AS total
FROM
foo f;

结果：

DAY_COL     TOTAL
2013-06-06  9
2013-06-05  12
2013-06-04  --
2013-06-03  --
2013-06-02  --

Answer 3

为了使查询更清晰，我建议你创建一个简单的函数：

DELIMITER $$
DROP FUNCTION IF EXISTS `getSum`$$
CREATE FUNCTION `getSum`(a DATE) RETURNS INT DETERMINISTIC
    BEGIN

        DECLARE ret INT DEFAULT 0;
        DECLARE ct INT DEFAULT 0;

        SELECT COUNT(Day_col), COALESCE(SUM(Value_col),0) INTO ct, ret 
        FROM YOUR_TABLE WHERE Day_col < a AND Day_col >= DATE_SUB(a,INTERVAL 3 DAY);

        IF(ct>=3) THEN RETURN ret;
        ELSE RETURN NULL;
        END IF;

    END$$

DELIMITER ;

然后，只需使用查询：

SELECT Day_col, IF(getSum(Day_col) IS NOT NULL, getSum(Day_col), '--') AS total FROM YOUR_TABLE

或者如果您想要排除日期' - '：

SELECT Day_col, getSum(Day_col) AS total FROM YOUR_TABLE WHERE getSum(Day_col) IS NOT NULL

只需将YOUR_TABLE更改为您的桌子名称......

我希望这会对你有所帮助！

MYSQL：选择总和（值）

3 个答案: