Question

我正在使用以下内容获得输出：

    2013-06-06 11:44:27.325 [2570:907] Rating: 0
    2013-06-06 11:44:27.326 [2570:907] Rating: 2
    2013-06-06 11:44:27.327 [2570:907] Rating: 3 


[rateQuery findObjectsInBackgroundWithBlock:^(NSArray *rateObjects, NSError *error)
 {
     if( !error )
     {
         NSLog(@"rateobject %@", rateObjects);

         for (id item in rateObjects) {

             int ratingVal = [[item objectForKey:@"Rating"] intValue];
             NSLog(@"Rating: %d", ratingVal);
         }

     }
 }
 ];

我希望添加数字以获得总数，然后除以计数以获得平均“评级”。

我试过这个，但显然语法不正确。我想我需要使用NSArray而不是“item”：

NSNumber *sum=[[item objectForKey:@"Rating"] valueForKeyPath:@"@sum.floatValue"];
                 NSLog(@"Rating Sum: %@", sum);

感谢您的帮助。

Answer 1

您可以使用KVC获得平均值。一个例子

NSArray *objects = @[
@{ @"Rating": @4 },
@{ @"Rating": @6 },
@{ @"Rating": @10 }
];

NSLog(@"Average: %@", [objects valueForKeyPath:@"@avg.Rating"]);
// results in "Average: 6.666666"

所以在你的情况下使用：

NSNumber *sum = [rateObjects valueForKeyPath:@"@sum.Rating"];
NSNumber *average = [rateObjects valueForKeyPath:@"@avg.Rating"];

Answer 2

试试这个：

__block float sum = 0;
[rateQuery findObjectsInBackgroundWithBlock:^(NSArray *rateObjects, NSError *error)  {
    if( !error )      {
        NSLog(@"rateobject %@", rateObjects);

        for (id item in rateObjects) {
            sum = sum + [[item objectForKey:@"Rating"] intValue];
            int ratingVal = [[item objectForKey:@"Rating"] intValue];
            NSLog(@"Rating: %d", ratingVal);
        }
        NSLog(@"Sum: %f", sum);
        NSLog(@"Average: %f", sum/rateObjects.count);
    }
}];

Answer 3

试试这个：

NSNumber *sum = [rateObjects valueForKeyPath:@"@sum.Rating"];

for for循环

添加NSArray中的所有值并找到平均值

3 个答案: