我在此gridview的每一行都有一个gridview和linkbuttons。当我单击其中一个按钮时,我会获得此行的courseName,courseCode和term列值的值。这是我的代码:
int row = -1;
int.TryParse(e.CommandArgument as string, out row);
GridViewRow gdrow = instCourses.Rows[row];
// *** Get the underlying data item - in this case a DataRow
DataRow dr = ((DataTable)this.instCourses.DataSource).Rows[gdrow.DataItemIndex];
// *** Retrieve our context
string courseCode = dr["CourseCode"].ToString();
string courseNumber = dr["CourseNumber"].ToString();
string term = dr["Term"].ToString();
SqlConnection con = new SqlConnection();
con.ConnectionString = Userfunctions.GetConnectionString();
con.Open();
SqlCommand cmd=new SqlCommand("select RegisterTable.StudentID,StudentTable.Name,StudentTable.Surname from RegisterTable INNER JOIN StudentTable where RegisterTable.StudentID=StudentTable.StudentID and RegisterTable.CourseCode=@courseCode and RegisterTable.Term=@term and RegisterTable.CourseNumber=@courseNumber",con);
cmd.Parameters.AddWithValue("@courseCode", courseCode);
cmd.Parameters.AddWithValue("@courseNumber", courseNumber);
cmd.Parameters.AddWithValue("@term", term);
SqlDataAdapter da = new SqlDataAdapter(cmd);
DataTable dt = new DataTable();
da.Fill(dt);
studList.DataSource = dt;
studList.DataBind();
这些值按照我的预期返回,但我认为我的查询有问题,它说关键字'where'附近的语法不正确。有谁能看到这个问题?
由于
答案 0 :(得分:5)
格式化您的SQL查询,您将看到问题:
select RegisterTable.StudentID,StudentTable.Name,StudentTable.Surname
from RegisterTable INNER JOIN StudentTable
where RegisterTable.StudentID=StudentTable.StudentID
and RegisterTable.CourseCode=@courseCode
and RegisterTable.Term=@term
and RegisterTable.CourseNumber=@courseNumber
联接中没有ON
子句。
from RegisterTable INNER JOIN StudentTable
ON RegisterTable.StudentID=StudentTable.StudentID
where ....
顺便说一句,在C#中你可以使用逐字string literal格式化你的sql:
string sql = @"
SELECT registertable.studentid,
studenttable.name,
studenttable.surname
FROM registertable
INNER JOIN studenttable
ON registertable.studentid = studenttable.studentid
WHERE registertable.coursecode = @courseCode
AND registertable.term = @term
AND registertable.coursenumber = @courseNumber";
然后在sql-queries中找到错误会更容易。
答案 1 :(得分:1)
你有一个内部联接,没有ON
select RegisterTable.StudentID,StudentTable.Name,StudentTable.Surname from RegisterTable INNER JOIN StudentTable ON RegisterTable.studentid = StudentTable .id where RegisterTable.StudentID=StudentTable.StudentID and RegisterTable.CourseCode=@courseCode and RegisterTable.Term=@term and RegisterTable.CourseNumber=@courseNumber
答案 2 :(得分:1)
你错过了这里的连接条件
FROM RegisterTable INNER JOIN StudentTable
你的内部联接应该是这样的
from RegisterTable INNER JOIN StudentTable
ON RegisterTable.StudentID = StudentTable.StudentId
根据您的where子句,您可以在不使用内部联接的情况下编写查询,只需使用笛卡尔积即可。
select
RegisterTable.StudentID,
StudentTable.Name,
StudentTable.Surname
from RegisterTable, StudentTable
where RegisterTable.StudentID=StudentTable.StudentID and
RegisterTable.CourseCode=@courseCode and
RegisterTable.Term=@term and
RegisterTable.CourseNumber=@courseNumber
答案 3 :(得分:1)
查询语法不正确。尝试:
SELECT
RegisterTable.StudentID,
StudentTable.Name,
StudentTable.Surname
FROM RegisterTable
INNER JOIN StudentTable ON RegisterTable.StudentID = StudentTable.StudentID
WHERE
RegisterTable.CourseCode = @courseCode
AND RegisterTable.Term = @term
AND RegisterTable.CourseNumber = @courseNumber
您需要将WHERE
更改为ON
才能完成JOIN
,然后您应将其余条件移至WHERE
子句。
答案 4 :(得分:1)
您需要使用StudentTable
而不是ON
指定每个表中哪个列加入WHERE
:
SELECT RegisterTable.StudentID, StudentTable.Name, StudentTable.Surname
FROM RegisterTable
INNER JOIN StudentTable ON RegisterTable.StudentID = StudentTable.StudentID
WHERE RegisterTable.CourseCode = @courseCode
AND RegisterTable.Term = @term
AND RegisterTable.CourseNumber = @courseNumber