我对hibernate和annotations的概念不熟悉。目前我在hibernate上对集合进行编程。
实际上以下是我的程序代码
person.class
package com;
import java.util.HashSet;
import java.util.Set;
import javax.persistence.ElementCollection;
import javax.persistence.Embedded;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;
@Entity
@Table(name = "PesonSubjects")
public class Person {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private int id;
private String name;
@ElementCollection
private Set<Subjects> subjectList = new HashSet<Subjects>();
public Set<Subjects> getSubjectList() {
return subjectList;
}
public void setSubjectList(Set<Subjects> subjectList) {
this.subjectList = subjectList;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
MAIN课程
package com;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.cfg.AnnotationConfiguration;
public class Personmain {
/**
* @param args
*/
public static void main(String[] args) {
SessionFactory sessionfactory = new AnnotationConfiguration()
.configure().buildSessionFactory();
Session session = sessionfactory.openSession();
session.beginTransaction();
Person person = new Person();
person.setName("vikram");
Subjects subjects1 = new Subjects();
subjects1.setAuthor("xxxxxxxx");
subjects1.setISBN(10111);
subjects1.setName("mein kampf");
subjects1.setPublicationHouse("tmh");
person.getSubjectList().add(subjects1);
Subjects subjects2 = new Subjects();
subjects2.setAuthor("bbbbb");
subjects2.setISBN(10112);
subjects2.setName("harry porter");
subjects2.setPublicationHouse("William");
person.getSubjectList().add(subjects2);
session.save(person);
session.getTransaction().commit();
session.close();
}
}
科目课
package com;
import javax.persistence.Embeddable;
@Embeddable
public class Subjects {
private int ISBN;
private String name;
private String Author;
private String publicationHouse;
public int getISBN() {
return ISBN;
}
public void setISBN(int iSBN) {
ISBN = iSBN;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getAuthor() {
return Author;
}
public void setAuthor(String author) {
Author = author;
}
public String getPublicationHouse() {
return publicationHouse;
}
public void setPublicationHouse(String publicationHouse) {
this.publicationHouse = publicationHouse;
}
}
我的配置文件
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<!-- Database connection settings -->
<property name="connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="connection.url">jdbc:mysql://localhost:3306/AnnotationCollections</property>
<property name="connection.username">root</property>
<property name="connection.password">cccccccc</property>
<property name="hbm2ddl.auto">create</property>
<!-- JDBC connection pool (use the built-in) -->
<property name="connection.pool_size">1</property>
<!-- SQL dialect -->
<property name="dialect">org.hibernate.dialect.MySQLDialect</property>
<!-- Echo all executed SQL to stdout -->
<property name="show_sql">true</property>
<mapping class="com.Person" />
</session-factory>
</hibernate-configuration>
现在通过该程序我想要一组主题进入一个表(我没有注释subjectList,因为我希望它是集合而不是表格格式) 即它应该将值存储在集合fomat
中但是我收到以下错误
log4j:WARN No appenders could be found for logger (org.hibernate.cfg.annotations.Version).
log4j:WARN Please initialize the log4j system properly.
Exception in thread "main" org.hibernate.MappingException: Could not determine type for: java.util.Set, for columns: [org.hibernate.mapping.Column(subjectList)]
at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:266)
at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:253)
at org.hibernate.mapping.Property.isValid(Property.java:185)
at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:410)
at org.hibernate.mapping.RootClass.validate(RootClass.java:192)
at org.hibernate.cfg.Configuration.validate(Configuration.java:1099)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1284)
at com.Personmain.main(Personmain.java:14)
还有别的东西要定义吗?
由于
答案 0 :(得分:1)
为安全起见,请保持两个类的映射:
<mapping class="com.Person" />
<mapping class="com.Subjects" />
除此之外,您的代码似乎在推断错误的访问类型。
尝试添加:
@javax.persistence.Access(javax.persistence.AccessType.FIELD)
到Person
。像:
@Entity
@Table(name = "PesonSubjects")
@javax.persistence.Access(javax.persistence.AccessType.FIELD)
public class Person {
如果不起作用,请尝试同时添加Person
和Subjects
。