Question

我希望有一个7/10的机会成功完成一个动作，比如爬墙。我无法使用random.randint获得一组整数，所以我不得不重新键入10次，如下所示：

import random

print('You try to climb the wall.')

climbResult = random.randint(1,10)


elif climbResult == (1):
    print('You were successful.')

elif climbResult == (2):
    print('You were successful.')

elif climbResult == (3):
    print('You were successful.')

elif climbResult == (4):
    print('You were successful.')

elif climbResult == (5):
    print('You were successful.')

elif climbResult == (6):
    print('You were successful.')

elif climbResult == (7):
    print('You were successful.')

elif climbResult == (8):
    print('You were unsuccessful.')

elif climbResult == (9):
    print('You were unsuccessful.')

elif climbResult == (10):
    print('You were unsuccessful.')

一遍又一遍地添加数字是一种痛苦，而这仅仅是10个部分。我只想制作两个if语句，一个有70％的机会打印你成功，另一个有30％的机会打印你没有成功。

对不起，这是一个非常简单的问题，我问的方式可能很难理解。我只学习了两个星期的Python，而且我用英语问它，因为它不是我的第一语言。

Answer 1

if climbResult <= 7:
     print('You were successful.')
else:
     print('You were unsuccessful.')

Answer 2

以一种稍微有趣和不同的方式来查看问题：

random.choice(['You were successful']*7 + ['You were unsuccessful']*3)

如果你不计算进口数量，这也是一个单行...这是必须的... ...

Answer 3

因为你说在70％的情况下你只关心这个说法“成功” 并且“不成功”的其他一切你也可以使用随机数。

# import random

def answer():
  if random.uniform(0, 10) < 7:
    return 'successful'
  else:
    return 'unsuccessful'

Answer 4

if climbResult <= 7: 
    print("Success")
else: 
    print ("Fail")

Answer 5

return climbResult in range(1,8)

如何缩短Python代码？

5 个答案: