Question

问题编号1 - 状态=已解决

使用过的表格为：

CREATE TABLE Rubriek(
rubrieknaam     char(50)        not null, /* char(24) */
rubrieknummer   numeric(38)     not null, /* numeric(3) */
rubriek         numeric(38)     null, /* numeric(3) */
volgnr          numeric(38)     not null, /* nuemric(2) */
constraint pk_rubrieknummer primary key(rubrieknummer),
constraint fk_rubriek foreign key(rubriek) references Rubriek (rubrieknummer)
)

我一直在尝试在PHP中创建一个垂直菜单，该菜单将填充所提供的表格，但我遇到了一些困难。我尝试了一些代码，但我不能让它为我工作:(。菜单包括类别（rubrieken）和子类别。

对表格进行更多说明：
rubrieknaam - ＆gt;类别名称
rubrieknummer - ＆gt;类别的id
rubriek - ＆gt;告诉我们一个类别是否属于子类别，如果不是，那么该值将为null

当我收到一些'通知：未定义的索引'错误时。更具体地说，有以下几行：

 if($parent != $menu['rubriek']){//if not seen item before
 echo "<li>".$menu['rubrieknummer']."</li>";//echo item
 if($parent != $menu['rubriek']){//if not seen before not then the value will be null:

我尝试了以下但是无济于事。

//connection to SQL Database
$connectionInfo = array( "UID"=>$uid,"PWD"=>$pwd,"Database"=>$databaseName);

//Connecting with SQL Authentication
$conn = sqlsrv_connect( $serverName, $connectionInfo);

$query = sqlsrv_query($conn, "SELECT * FROM Rubriek");
$parent=0;
$sub=0;
echo "<ul>";//start list
while($menu = sqlsrv_fetch_array($query)){
   if($parent != $menu['rubriek']){//if not seen item before
      if($sub != 0){echo "</ul>";}else{$sub++;}//if not first submenu, close submenu before. If first sub sub++.
      echo "<ul>";}//open submenu
   echo "<li>".$menu['rubrieknaam']."</li>";//echo item
   if($parent != $menu['rubriek']){//if not seen before
      $parent = $menu['rubriek']; //set to seen before so next loop will be recognised
   }
}
echo "</ul>"; //end list
?>

问题编号2

我已经实施了提到的修复皇家BG，它的工作原理！但现在有一个不同的问题。我还想实现子类别，我为几个类别创建了子类别。

例如，我制作了下一个测试数据：

    Rubrieknaam          | rubrieknummer | rubriek
    (= Name of Category) | (=Category ID)| (=Category is a subcategory of the following category):
     ----------------------------------------------------------------------------------
     Cars                | 1             | Null
     Audio               | 2             | Null
     Ford                | 3             | 1 (subcategory of Cars)
     Toyota              | 4             | 1 (subcategory of Cars)
     Speakers            | 5             | 2 (subcategory of Audio)
     Microphones         | 6             | 2 (subcategory of Audio)
     Instruments         | 7             | Null
     Guitar              | 8             | 7 (subcategory of Instruments)

记录按此顺序列在数据库中。前两个类别列为一个类别。其余的都列为'音频'的子类别，即使'乐器'应该是一个新的类别而不是子类别。

Answer 1

$query = sqlsrv_query($conn, "SELECT rubrieknaam FROM Rubriek");

...

while($menu = sqlsrv_fetch_array($query)){
   if($parent != $menu['rubriek']){//if not seen item before

您只选择了一列 - ＆gt; rubrieknaam，您正在请求名为rubriek和rubrieknumer的列。您还需要选择它们，以便在获取时使用它们。

用PHP创建一个垂直菜单并用SQL填充它

1 个答案: