基本上我有以下查询,我试图区分这个独特的排名:
WITH numbered_rows
as (
SELECT Claim,
reserve,
time,
RANK() OVER (PARTITION BY ClaimNumber ORDER BY time asc) as 'Rank'
FROM (
SELECT cc.Claim,
MAX(csd.time) as time,
csd.reserve
FROM ClaimData csd WITH (NOLOCK)
JOIN Core cc WITH (NOLOCK)
on cc.ClaimID = csd.ClaimID
GROUP BY cc.Claim, csd.Reserve
) as t
)
select *
from numbered_rows cur, numbered_rows prev
where cur.Claim= prev.Claim
and cur.Rank = prev.Rank -1
我得到的结果如下:
Claim reserve Time Rank Claim reserve Time Rank
--------------------------------------------------------------------
11 0 12/10/2012 1 11 15000 5/30/2013 2
34 2000 1/21/2013 1 34 750 1/31/2013 2
34 750 1/31/2013 2 34 0 3/31/2013 3
07 800000 5/9/2013 1 07 0 5/10/2013 2
但我只想看到以下内容:(已将34级排名2删除,因为它不是最高的
Claim reserve Time Rank Claim reserve Time Rank
--------------------------------------------------------------------
11 0 12/10/2012 1 11 15000 5/30/2013 2
34 750 1/31/2013 2 34 0 3/31/2013 3
07 800000 5/9/2013 1 07 0 5/10/2013 2
答案 0 :(得分:2)
我认为你可以通过颠倒你的逻辑来做到这一点,即按时间顺序DESC,在最终选择中切换cur和prev并在最终选择中将-1更改为+1,然后将prev.rank限制为1,因此,确保您只包含每项索赔的最新2个结果:
WITH numbered_rows AS
( SELECT Claim,
reserve,
time,
[Rank] = RANK() OVER (PARTITION BY ClaimNumber ORDER BY time DESC)
FROM ( SELECT cc.Claim,
[Time] = MAX(csd.time),
csd.reserve
FROM ClaimData AS csd WITH (NOLOCK)
INNER JOIN JOIN Core AS cc WITH (NOLOCK)
ON cc.ClaimID = csd.ClaimID
GROUP BY cc.Claim, csd.Reserve
) t
)
SELECT *
FROM numbered_rows AS prev
INNER JOIN numbered_rows AS cur
ON cur.Claim= prev.Claim
AND cur.Rank = prev.Rank + 1
WHERE prev.Rank = 1;