Question

我有一组价值tgat代表平均每个帖子中的人数。这些是pcode1 = 239，pcode2 = 245，pcode3 = 210和pcode4 = 217现在就是我被卡住的地方。我假设平均值为allpcode = 220。

有没有办法在python中编写代码，以便我可以将每个pcode与总平均值进行比较？我想要做的就是比较pcode1到allpcode，如果pcode1高于/低于allpcode，则显示pcode1的平均值，然后说{ {1}}低于pcode1或高于allpcode。然后我想重复所有其他的pcodes :)

我想在屏幕上显示所有较低的平均值和所有较高的平均值。

因此，像pcode 3和4平均值低于所有pcode平均值，pcode 1和2高于所有p代码。

是否可以创建这样的代码，因为我不知道如何/从哪里开始？

Answer 1

在这种情况下，您经常想要迭代所有一组值，通常最好使用单个list，dict或其他集合变量，而不是一堆单独的变量。例如：

pcodes = {1: 239, 2: 245, 3: 210, 4: 217}

现在您可以编写如下代码：

pcodes = {1: 239, 2: 245, 3: 210, 4: 217}
allpcode = 220

for pcode, value in pcodes.items():
    if value < allpcode:
        print('code {} is lower than allpcode'.format(pcode))
    elif value > allpcode:
        print('code {} is higher than allpcode'.format(pcode))

如果确实希望拥有单独的变量，则必须做更多工作，如下所示：

pcode1 = 239
pcode2 = 245
pcode3 = 210
pcode4 = 217
allpcode = 220

for i, value in enumerate((pcode1, pcode2, pcode3, pcode4)):
    if value < allpcode:
        print('code {} is lower than allpcode'.format(i + 1))
    elif value > allpcode:
        print('code {} is higher than allpcode'.format(i + 1))

Answer 2

如果您只想匹配值，可以使用列表：

>>> pcode1 = 239
>>> pcode2 = 245
>>> pcode3 = 210
>>> pcode4 = 217
>>> lis = [pcode1, pcode2, pcode3, pcode4]
>>> allpcode= 220

>>> for i,x in enumerate(lis):
    if x < allpcode:
        print "pcode{} is less than {}".format(i+1,allpcode)
    elif x > allpcode:    
        print "pcode{} is greater than {}".format(i+1,allpcode)
...         
pcode1 is greater than 220
pcode2 is greater than 220
pcode3 is less than 220
pcode4 is less than 220

更好地使用字典：

因为变量只是对python中值的引用，所以你不能访问变量名称。如果你有很多pcodes，那么为每一个定义一个变量是解决这个问题的坏方法，使用dict会更加清晰。

#create dictionary with keys named pcode1, pcode2,...     
>>> dic = {'pcode1':239, 'pcode2':245, 'pcode3':210, 'pcode4':217}

>>> for k,v in dic.items():
    if v < allpcode:
        print "{} is less than {}".format(k ,'allpcode')
    elif v > allpcode:    
        print "{} is greater than {}".format(k,'allpcode')
...         
pcode3 is less than allpcode
pcode2 is greater than allpcode
pcode1 is greater than allpcode
pcode4 is less than allpcode

虽然词典没有维护任何订单，但您可能需要collections.OrderedDict或sorted来获取特定订单中的密钥。

计算python中的平均值和比较

2 个答案: