Question

我想创建一个用户输入几个名字的程序，然后选择一个随机名称。但是，我无法弄清楚如何获取字符串。我希望将每个字符串分配给一个int，然后选择一个int时，字符串也是如此。请帮帮我。

    #include <iostream>
    #include <ctime>
    #include <cstdlib>
    #include <string>
    using namespace std;
    void randName()
    {
        string name;//the name of the entered person
        cout << "write the names of the people you want."; 
            cout << " When you are done, write done." << endl;
        int hold = 0;//holds the value of the number of people that were entered
        while(name!="done")
        {
            cin >> name;
            hold ++;
        }
        srand(time(0));
        rand()&hold;//calculates a random number
    }
    int main()
    {
        void randName();
        system("PAUSE");
    }

Answer 1

您可以使用std::vector<std::string>来存储名称，并将int作为索引。然后使用随机选择其中一个名称。

Answer 2

你需要某种容器来存储你的名字。vector是完美的。

std::string RandName()
{
  std::string in;
  std::vector<std::string> nameList;

  cout << "write the names of the people you want."; 
  cout << " When you are done, write done." << endl;       

  cin >> in; // You'll want to do this first, otherwise the first entry could
             // be "none", and it will add it to the list.
  while(in != "done")
  {
    nameList.push_back(in);
    cin >> in;
  }    

  if (!nameList.empty())
  {
    srand(time(NULL)); // Don't see 0, you'll get the same entry every time.
    int index = rand() % nameList.size() - 1; // Random in range of list;

    return nameList[index];      
  }
  return "";
}

如 billz 所述，您的main()也存在问题。您希望调用您的函数，因此您不需要void关键字。这个新函数也会返回一个字符串，这样它实际上很有用。

int main()
{
    std::string myRandomName = randName();
    system("PAUSE");
}

c ++ - while循环，字符串和整数

2 个答案: