Question

我正在尝试删除iOS中字符串中的所有括号。看到这个stackoverflow帖子：how to remove spaces, brackets and " from nsarray

答案：

NSCharacterSet *charsToTrim = [NSCharacterSet characterSetWithCharactersInString:@"()"];
s = [s stringByTrimmingCharactersInSet:charsToTrim];

但这只是删除一个括号（来自mystring。如何删除所有这些？

我的代码如下所示：

NSCharacterSet *charsToTrim = [NSCharacterSet characterSetWithCharactersInString:@"( )"];
attributedLabel.text = [attributedLabel.text stringByTrimmingCharactersInSet:charsToTrim];
NSLog(@"%@",attributedLabel.text);

需要一些指导...

Answer 1

尝试使用
[[attributedLabel.text stringByReplacingOccurrencesOfString:@"(" withString:@""] stringByReplacingOccurrencesOfString:@")" withString:@""];
代替。

Answer 2

以下代码正在运作

NSString *str=[[NSBundle mainBundle] objectForInfoDictionaryKey:@"string"];
NSLog(@"%@",[[str stringByReplacingOccurrencesOfString:@")" withString:@""] stringByReplacingOccurrencesOfString:@"(" withString:@""]);

Answer 3

只需按照以下方式执行此操作：

NSString *finalStr = [initialStr stringByReplacingOccurenceOfString:@"(" withString:@""];
finalStr = [finalStr stringByReplacingOccurenceOfString:@")" withString:@""];

这将从字符串中删除所有括号：我在此开发人员blog上找到了这个答案

Answer 4

Swift 4.2使用replacingOccurrences

例如从（Pizza）获取披萨

let foodWithParentheses = "(Pizza)"

let pizzaWithoutParen = foodWithParentheses.replacingOccurrences(of: "(", with: "").replacingOccurrences(of: ")", with: "")

print(pizzaWithoutParen)
// output: Pizza

从iOS中的字符串中删除括号

4 个答案: