Question

我正在将CSV文件导入到SQL Server

我从Internet上获得了代码..工作正常但是当我将一个额外的字段（User_Id）与该CSV文件添加到SQL时，这就是错误....我无法理解错误在哪里... ..码... DataTable tblReadCSV = new DataTable（）;

            tblReadCSV.Columns.Add("Name");
            tblReadCSV.Columns.Add("Email");
            tblReadCSV.Columns.Add("Mobile");

            tblReadCSV.Columns.Add("User_id");
            string path = System.IO.Path.GetFileName(FileUpload1.PostedFile.FileName);

            FileUpload1.PostedFile.SaveAs(Server.MapPath("~/Email/UploadFile/" + path));
            path = Server.MapPath("~/Email/UploadFile/" + path);
            TextFieldParser csvParser = new TextFieldParser(path);
             csvParser.Delimiters = new string[] { "," };
            csvParser.TrimWhiteSpace = true;
            csvParser.ReadLine();

            while (!(csvParser.EndOfData == true))
            {
                tblReadCSV.Rows.Add(csvParser.ReadFields());
            }
            string strCon = ConfigurationManager.ConnectionStrings["con"].ConnectionString;
            string strSql = "Insert into Contacts(Name,Email,Mobile,User_id ) values(@Name,@Email,@Mobile," + UserId +")";
            SqlConnection con = new SqlConnection(strCon);
            SqlCommand cmd = new SqlCommand();
            cmd.CommandType = CommandType.Text;
            cmd.CommandText = strSql;
            cmd.Connection = con;               
            cmd.Parameters.Add("@Name", SqlDbType.VarChar, 50, "Name");
            cmd.Parameters.Add("@Email", SqlDbType.VarChar, 50, "Email");
            cmd.Parameters.Add("@Mobile", SqlDbType.VarChar, 50, "Mobile");

            cmd.Parameters.Add("@User_id", SqlDbType.Int , UserId);

            SqlDataAdapter dAdapter = new SqlDataAdapter();
            dAdapter.InsertCommand = cmd;
            int result = dAdapter.Update(tblReadCSV);
            Label1.Text = "File successfully uploaded";

Answer 1

你没有说出错误信息是什么，也没有说出现在哪里，但在我看来这行

string strSql = "Insert into Contacts(Name,Email,Mobile,User_id ) values(@Name,@Email,@Mobile," + UserId +")";

应该是这样的

string strSql = "Insert into Contacts(Name,Email,Mobile,User_id ) values(@Name,@Email,@Mobile,@User_id)";

Answer 2

替换

string strSql = "Insert into Contacts(Name,Email,Mobile,User_id)
values(@Name,@Email,@Mobile," + UserId +")";

与

string strSql = "Insert into Contacts(Name,Email,Mobile,User_id )
values(@Name,@Email,@Mobile,@UserId)";

在上面一行中，您只是声明参数。

这就是你实际传递当前用户ID的方式：

cmd.Parameters.Add("@User_id", SqlDbType.Int , UserId);

试试这个;希望它能奏效。

Answer 3

值（@ Name，@ Email，@ Mobile，＆＃34; + UserId +＆＃34;）＆＃34; //来自你的来源

avoid ''+ UserId +'' in your string strSql..

CSV文件导入到SQL Server错误

3 个答案: