如何从下面的代码中替换basic.hml中的URL?
代码是
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
<html>
<head>
<!-- swfobject is a commonly used library to embed Flash content -->
<script type="text/javascript"
src="https://ajax.googleapis.com/ajax/libs/swfobject/2.2/swfobject.js"></script>
<!-- Setup the recorder interface -->
<script type="text/javascript" src="recorder.js"></script>
<script>
function setup() {
Wami.setup("wami");
}
function record() {
status("Recording...");
Wami.startRecording("https://wami-recorder.appspot.com/audio");
}
function play() {
Wami.startPlaying("https://wami-recorder.appspot.com/audio");
}
function stop() {
status("");
Wami.stopRecording();
Wami.stopPlaying();
}
function status(msg) {
document.getElementById('status').innerHTML = msg;
}
</script>
</head>
<body onload="setup()">
<input type="button" value="Record" onclick="record()"></input>
<input type="button" value="Stop" onclick="stop()"></input>
<input type="button" value="Play" onclick="play()"></input>
<div id="status"></div>
<div id="wami"></div>
</body>
</html>
答案 0 :(得分:0)
您可以使用以下内容替换网址:
Wami.startRecording("http://www.example.com/record.php?filename=test.wav");
和
Wami.startPlaying("http://www.example.com/test.wav");
record.php可能是:
<?php
// get the filename
parse_str($_SERVER['QUERY_STRING'], $params);
$file = isset($params['filename']) ? $params['filename'] : 'temp.wav';
// save the recorded audio to that file
$content = file_get_contents('php://input');
$fh = fopen($file, 'w') or die("can't open file");
fwrite($fh, $content);
fclose($fh);
?>