Question

我想创建一个代码来检查精确列中的值是否等于'neodobren'，并且列中是否有这样的值来回显“添加成员”按钮，并为每个值回显。我试图做以下事情并没有回应是：我有以下MySQL表格内容：

UID Name    Phone   Email   SchoolGymnasium City    Password    Status  
1                                                               neodobren
2                                                               neodobren

我在HTML索引页面中有以下PHP代码：

$con = mysql_connect("localhost","****","****");
mysql_query("SET NAMES UTF8");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("***", $con);
include("../../sql.php");
session_start();
$zaqvki = mysql_query("SELECT * FROM Directors WHERE Status='neodobren' LIMIT 1");
            if(mysql_num_rows($zaqvki) > 0) {
echo '<div align="right"><a href="add/director/" class="btn add-project">Add Member</a></div><br>';

        // display data in table


        // loop through results of database query, displaying them in the table
        while($row = mysql_fetch_array($zaqvki)) {  //$zaqvki was $result, before a guy comment me this...

                echo "Yes"; 
        } }
         else { 
                echo "No";
                }

它只显示按钮添加成员，而不显示是，必须回显。

Answer 1

使用mysql_fetch_assoc获取关联数组并对某列的每一行进行比较：

while($row = mysql_fetch_assoc($result)) 
{
    if($row['Status'] === 'neodobren')
        echo "Yes";
    else
        echo "No";
}

无法回应正确的结果。 PHP / MySQL的

1 个答案: