如何使用node.js中的参数HTTP获取请求?

时间:2013-05-24 20:02:45

标签: javascript node.js url parameters request

我正在使用'request'模块与NODE.js合作:

有效:

var request = require('request');
request('http://www.site.com', function (error, response, body) {
  if (!error && response.statusCode == 200) {
    console.log(body);
  }
});

当我尝试包含参数时,它会崩溃!

var request = require('request');
request('http://www.site.com/index.php?action=y9sadf98yh', function (error, response, body) {
  if (!error && response.statusCode == 200) {
    console.log(body);
  }
});

Error: undefined is not a valid uri or options object.
    at request (/node_modules/request/index.js:1217:41)
    at Request._callback (nodeCloseSession/index.js:60:5)
    at Request.self.callback (/node_modules/request/index.js:148:22)
    at Request.EventEmitter.emit (events.js:98:17)
    at Request.<anonymous> (/node_modules/request/index.js:876:14)
    at Request.EventEmitter.emit (events.js:117:20)
    at IncomingMessage.<anonymous> (/node_modules/request/index.js:827:12)
    at IncomingMessage.EventEmitter.emit (events.js:117:20)
    at _stream_readable.js:883:14
    at process._tickCallback (node.js:415:13)

如何在NODE.js'request'模块中使用参数?

2 个答案:

答案 0 :(得分:3)

您可以尝试使用Requestify作为替代方案,一个用于nodeJS +的小而简单的HTTP客户端,它支持缓存..

要执行您的请求,请执行以下操作:

var requestify = require('requestify');

requestify.get('http://www.site.com/index.php?action=y9sadf98yh')
  .then(function(response) {
      // Get the response body (JSON parsed or jQuery object for XMLs)
      response.getBody();
  }
);

或者:

var requestify = require('requestify');

requestify.get('http://www.site.com/index.php', { 
    params: {
      action: 'y9sadf98yh'
    }
})
  .then(function(response) {
      // Get the response body (JSON parsed or jQuery object for XMLs)
      response.getBody();
  }
);

答案 1 :(得分:0)

request('/www.site.com/', function (error, response, body) {
  if (!error && response.statusCode == 200) {
    console.log(body);
  }
});

使用用户代理获取参数值