Question

我试图覆盖JAXB编码中特殊字符的转义。为此我使用了一个实现CharacterEscapeHandler的接口。

这是界面：

package project1;
import com.sun.xml.bind.marshaller.CharacterEscapeHandler;
import java.io.IOException;
import java.io.Writer;
public class MinimumEsc implements CharacterEscapeHandler {
    private MinimumEsc( ) {

        System.out.println("Function called");


    }  // no instanciation please

    public static final CharacterEscapeHandler theInstance = new MinimumEsc(); 


    public void escape(char[] ch, int start, int length, boolean isAttVal, Writer out) throws IOException {
            // avoid calling the Writerwrite method too much by assuming
            // that the escaping occurs rarely.
            // profiling revealed that this is faster than the naive code.

            System.out.println("Function called");
            int limit = start+length;
            for (int i = start; i < limit; i++) {
                char c = ch[i];
                if( c=='&' || c=='<' || c=='>' || (c=='\"' && isAttVal) ) {
                    if(i!=start)
                        out.write(ch,start,i-start);
                    start = i+1;
                 switch (ch[i]) {
                    case '&' :
                        out.write("&amp2;");
                        break;
                    case '<' :
                        out.write("&lt2;");
                        break;
                    case '>' :
                        out.write("&gt2;");
                        break;
                    case '\"' :
                        out.write("&quot2;");
                        break;
                    }
                }
            }

            if( start!=limit )
                out.write(ch,start,limit-start);
        }
}

从我的主要课程我试图调用marshal方法：

public static void main(String[] args){
    System.out.println("hello world");



    try{
        //generate the java object
        Shiporder so = new Shiporder();
        so.setOrderid("123456");
        so.setOrderperson("Elio  < > ' \"  e  <> \" Khattar");


        //generate the file
        File f = new File("C:\\tst_encode.xml");
        if(!f.exists()){
          f.createNewFile();
        }


        JAXBContext context = JAXBContext.newInstance("xsdobjects");
        Marshaller jaxbMarshaller = context.createMarshaller();
     //  Marshaller jaxbMarshaller=  new JAXBContext().newMarshaller();


        System.out.println(CharacterEscapeHandler.class.getName());
        CharacterEscapeHandler escapeHandler =  MinimumEsc.theInstance;
        jaxbMarshaller.setProperty("com.sun.xml.bind.characterEscapeHandler",escapeHandler);



        jaxbMarshaller.marshal(so, f);
    }catch(JAXBException e){
        e.getCause();
        e.getErrorCode();
        e.printStackTrace();

    }catch(IOException ioe){
        ioe.printStackTrace();        
    }
}

当我运行它时，我收到了这个错误消息：

javax.xml.bind.PropertyException: name: com.sun.xml.bind.characterEscapeHandler value: project1.MinimumEsc@100bac2
    at org.eclipse.persistence.jaxb.JAXBMarshaller.setProperty(JAXBMarshaller.java:520)
    at project1.Class1.main(Class1.java:56)

可以请任何人帮助我吗？我花了最近5个小时在网上搜索它并尝试了很多解决方案。任何帮助都非常感谢。谢谢

Answer 1

根据堆栈跟踪，您使用EclipseLink MOXy作为JAXB (JSR-222)提供商。我们在EclipseLink 2.4中添加了对参考实现com.sun.xml.bind.CharacterEscapeHandler的支持。在EclipseLink发布之前，您将获得您所看到的异常。

<强>更新

您可能会遇到以下错误，该错误已在EclipseLink 2.5.1流中修复。

http://bugs.eclipse.org/406593

您可以从以下位置下载每晚版本：

http://www.eclipse.org/eclipselink/downloads/nightly.php

JAXB Marshal setProperty com.sun.xml.bind.CharacterEscapeHandler

1 个答案: