Question

我有一列按钮，必须与第一个按钮做同样的事情，但有自己的个人照片。如何设置ID以便没有故障？现在我有三个按钮设置，但他们以某种方式复制了相同的名称（他们都说移动快速洗）！这是我到目前为止http://ultimatefinishdetailing.com/Services.html

HTML :(在图片按钮上张贴HTML）

<STYLE MEDIA="screen" TYPE="text/css">
.pop-up {
    height: 100px;
    width: 100px;
    margin-right: -100px;
    margin-top: -100px;
    position:absolute;
right:-50px;
top:75px;
}
.button {
      width:300px;
      height:21px;
      display:block; background-image:url(images/button_ufad4.jpg);
      position:absolute;
}
</style>
<a href="" class="button" onmouseover="javascript:ShowImage('images/InteriorandExteriorDetailing.jpg')" onmouseout="javascript:HideImage()"></a>

<div id="popup" class="pop-up">
   <img id="popupImage" alt="" /> 
</div>

使用Javascript：

<script type="text/javascript">
    function ShowImage(src)
    {
        var img = document.getElementById('popupImage');
        var div = document.getElementById('popup');
        img.src = src;
        div.style.display = "block";
    }
    function HideImage()
    {
        document.getElementById('popup').style.display = "none";
    }
</script>

Answer 1

想出来！为每个按钮使用不同的id，类。下面的示例是一个按钮，为每个其他按钮更改id / classes的数量

HTML：1。CSS（样式）必须拥有自己的ID EX :(。pop-up1,2,3等; .button1,2,3等） 2. <A>（锚标记）必须有自己的id和类EX :( ID = BUTTON1,2,3等; CLASS = button1,2,3等） 3. div标签<div>必须拥有它自己的id，类，图像ID EX :( DIV ID =“popup1”，CLASS =“pop-up1”，IMG ID =“popupImage1

<STYLE MEDIA="screen" TYPE="text/css">
.pop-up1 {height: 100px;width: 100px;margin-right:-100px;margin-top:-100px;position:absolute;display:none;right:-50px;top: 75px;opacity:.7;z-index: 1}
.button1 {
      width:300px;
      height:21px;
      display:block; background-image:url(images/button_ufad4.gif);
      position:absolute;
}
.button1:hover {    background-position:left 43px;
}
</STYLE>
<A ID="BUTTON1" HREF="" CLASS="button1" ONMOUSEOVER="javascript:ShowImage('images/ufad2servicesexteriorandinteriordetailing.gif')" ONMOUSEOUT="javascript:HideImage()"></A>
<DIV ID="popup1" CLASS="pop-up1">
<IMG ID="popupImage1"> 
</DIV>

使用Javascript：

<script type="text/javascript">
    function ShowImage(src)
    {
        var img= document.getElementById('popupImage1');
        var div= document.getElementById('popup1');
        img.src=src;
        div.style.display="block";
    }
    function HideImage()
    { document.getElementById('popup1').style.display ="none";}
</script>

如何正确设置单个鼠标悬停按钮的ID

1 个答案: