Question

我希望使用Flask来托管单页网站，该网站允许用户上传将被解析并放入数据库的CSV。所有的数据库恶作剧都是完整的（通过另一个Python脚本中的SQLalchemy），一旦脚本可以访问CSV，我就可以解决所有问题，我只需要帮助就可以实现它。

以下是该方案：

1. User directs browser at URL (probably something like 
   http://xxx.xxx.xxx.xxx/upload/)
2. User chooses CSV to upload
3. User presses upload
4. File is uploaded and processed, but user is sent to a thank you page while our
   script is still working on the CSV (so that their disconnect doesn't cause the
   script to abort).

如果CSV留在服务器上，那就太酷了（事实上，它可能是首选，因为我们有备份，以防处理出错）

我认为我想要的是一个监听套接字的守护进程，但我对此并不熟悉，也不知道从哪里开始配置或设置Flask。

如果你觉得除了Flask之外的其他框架会更容易，那么请告诉我，我并不喜欢Flask，我只是读到它很容易设置！

非常感谢!!

Answer 1

以下是基于cook book example处理web.py中文件上传的（非常简单的简化）示例（Flash示例，我的经验较少，看起来更简单）：

import web

urls = ('/', 'Upload')

class Upload:
    def GET(self):
        web.header("Content-Type","text/html; charset=utf-8")
        return """
               <form method="POST" enctype="multipart/form-data" action="">
               <input type="file" name="myfile" />
               <br/>
               <input type="submit" />
               """

    def POST(self):
        x = web.input(myfile={})
        filedir = '/uploads' # change this to the directory you want to store the file in.
        if 'myfile' in x: # to check if the file-object is created
            filepath=x.myfile.filename.replace('\\','/') # replaces the windows-style slashes with linux ones.
            filename=filepath.split('/')[-1] # splits the and chooses the last part (the filename with extension)
            fout = open(filedir +'/'+ filename,'wb') # creates the file where the uploaded file should be stored
            fout.write(x.myfile.file.read()) # writes the uploaded file to the newly created file.
            fout.close() # closes the file, upload complete.
        raise web.seeother('/')

if __name__ == "__main__":
   app = web.application(urls, globals()) 
   app.run()

这会呈现一个上传表单，然后（在POST上）读取上传的文件并将其保存到指定的路径。

将CSV上传到Flask进行后台处理

1 个答案: