我正在向URL发送请求XML并接收到给定路径的zip文件。 有时我在这个zip文件的带宽很低时遇到麻烦,很可能120MB大小没有正确下载。并在解压缩zip文件时出错。从代码中提取也是如此。当我以高带宽下载时,这个文件可以毫无问题地下载。
我正在寻找一种解决方案而不会带宽高,从程序级别有没有办法下载这个zip文件,可能是部分或类似的东西?或者您所拥有的任何其他解决方案都非常感谢。
下载:
url = new URL(_URL);
sc = (HttpURLConnection) url.openConnection();
sc.setDoInput(true);
sc.setDoOutput(true);
sc.setRequestMethod("POST");
sc.connect();
OutputStream mOstr = sc.getOutputStream();
mOstr.write(request.getBytes());
InputStream in = sc.getInputStream();
FileOutputStream out = new FileOutputStream(path);
int count;
byte[] buffer = new byte[86384];
while ((count = in.read(buffer,0,buffer.length)) > 0)
out.write(buffer, 0, count);
out.close();
摘录:
try {
ZipFile zipFile = new ZipFile(path+zFile);
Enumeration<?> enu = zipFile.entries();
while (enu.hasMoreElements()) {
ZipEntry zipEntry = (ZipEntry) enu.nextElement();
String name = path+"/data_FILES/"+zipEntry.getName();
long size = zipEntry.getSize();
long compressedSize = zipEntry.getCompressedSize();
System.out.printf("name: %-20s | size: %6d | compressed size: %6d\n", name, size, compressedSize);
File file = new File(name);
if (name.endsWith("/")) {
file.mkdirs();
continue;
}
File parent = file.getParentFile();
if (parent != null) {
parent.mkdirs();
}
InputStream is = zipFile.getInputStream(zipEntry);
FileOutputStream fos = new FileOutputStream(file);
byte[] bytes = new byte[86384];
int length;
while ((length = is.read(bytes)) >= 0) {
fos.write(bytes, 0, length);
}
is.close();
fos.close();
}
zipFile.close();
} catch (Exception e) {
log("Error in extracting zip file ");
e.printStackTrace();
}