Question

我是python的新手我正在尝试分配变量，它说语法错误

protocol = input.readLine()
connectUrlHttp='http'
connectUrlHttps='https'


if protocol== "t3s":
 connectUrl=connectUrlHttps
elif protocol== "iiops":
  connectUrl=connectUrlHttps
else:
connectUrl=connectUrlHttp


  sca_deployComposite(connectUrl"://"+host+":"+port,emdroot+"/"+compositeLoc,owrite,user, password,default)

我面临以下错误

(no code object) at line 0
  File "/scratch/agentHome/sdappaji2/core/12.1.0.3.0/EMStage/PAF/DeployCompositesDP1367835748253/deploycompositesscripts/deployComposites.py", line 36
    connectUrl=connectUrlHttp

请指导我并给出一些指示

Answer 1

在Python中，indentation级别很重要：

每个缩进级别使用4个空格。

- PEP 8 -- Style Guide for Python Code

您的代码应该如下所示：

protocol = input.readLine()
connectUrlHttp = 'http'
connectUrlHttps = 'https'

if protocol == "t3s":
    connectUrl = connectUrlHttps
elif protocol == "iiops":
    connectUrl = connectUrlHttps
else:
    connectUrl = connectUrlHttp

# Note the `+` after `connectUrl` on the next line:
sca_deployComposite(connectUrl + "://" + host + ":" + port, emdroot + "/" +
                    compositeLoc, owrite, user, password, default)

Answer 2

实际的语法错误在这里：

sca_deployComposite(connectUrl"://"+host+":"+port,emdroot+"/"+compositeLoc,owrite,user, password,default)
                            ^^^

你可能错过了+那里。

Ashwini指出，else之后的缩进也是错误的。

Answer 3

else:

后，您的代码未正确缩进

if protocol== "t3s":
 connectUrl=connectUrlHttps
elif protocol== "iiops":
  connectUrl=connectUrlHttps
else:
    connectUrl=connectUrlHttp

sca_deployComposite(connectUrl+"://"+host+":"+port,emdroot+"/"+compositeLoc,owrite,user, password,default)

另外，您在+之后错过了sca_deployComposite(connectUrl。

分配变量时Python语法错误

3 个答案: