Question

int numberofbutton=x;将会提供。

我试图循环但是我失败了因为numberofbutton必须能被3整除。我不能写算法。

基于numberofbutton，我们必须以编程方式循环TableRow中的三个按钮我的意思是，如果numberofbutton 4 ，

TableRow[0]->Button Button Button
TableRow[1]->Button

如果 3 ，

TableRow[0]->Button Button Button

更新根据ZouZou的回答，代码在下面但尚未解决，因为tr []未定义：

int bn = 9;
        if (bn % 3 == 0) {
            TableRow[] tr = new TableRow[bn / 3];
            for (int i = 1; i <=(bn / 3); i++) {
                tr[i] = new TableRow(this);
            }
        } else {
            TableRow[] tr = new TableRow[(bn / 3) + 1];
            for (int i = 1; i <=(bn / 3) + 1; i++) {
                tr[i] = new TableRow(this);
            }
        }
        Button[] b=new Button[bn];
        for(int i=1;i<=bn;i++){
            b[i]=new Button(this);
        }
        int index = -1;
        for (int i = 0; i < bn; i++) {
            if(i%3==0){
                index+=1;
                tr[index].addView(b[i]);
            }else{
                tr[index].addView(b[i]);
            }
        }

的更新：

完整代码，但为什么不起作用？：

@Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        TableLayout tL = (TableLayout) findViewById(R.id.table);

        int bn = 9;

        TableRow[] tr = null;

        if (bn % 3 == 0) {
            tr = new TableRow[bn / 3];
            for (int i = 1; i <= (bn / 3); i++) {
                tr[i] = new TableRow(this);
            }
        } else {
            tr = new TableRow[(bn / 3) + 1];
            for (int i = 1; i <= (bn / 3) + 1; i++) {
                tr[i] = new TableRow(this);
            }
        }

        Button[] b=new Button[bn];

        for(int i=1;i<=bn;i++){
            b[i]=new Button(this);
        }

        int index = -1;

        for (int i = 0; i < bn; i++) {
            if(i%3==0){
                index+=1;
                tr[index].addView(b[i]);
                tL.addView(tr[index]);
            }else{
                tr[index].addView(b[i]);
            }

        }

    }

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:paddingBottom="@dimen/activity_vertical_margin"
    android:paddingLeft="@dimen/activity_horizontal_margin"
    android:paddingRight="@dimen/activity_horizontal_margin"
    android:paddingTop="@dimen/activity_vertical_margin"
    tools:context=".MainActivity" >

    <TableLayout
        android:id="@+id/table"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_alignParentLeft="true"
        android:layout_alignParentTop="true"
        android:layout_marginLeft="59dp"
        android:layout_marginTop="44dp" >
    </TableLayout>

</RelativeLayout>

Answer 1

您可以使用modulo执行此类操作：

int index = -1;

for(int i = 0; i < numberButtons; i++){
        if(i%3 == 0) {
          index += 1;
          tableRow[index] <- add Button here //here it's a new row we update the index
        }
        else
          tableRow[index] <- add Button here //we can add button to the current index
                                             //because there are less than 3 buttons
}

编辑：

替换：

int bn = 9;
        if (bn % 3 == 0) {
            TableRow[] tr = new TableRow[bn / 3];
            for (int i = 1; i <=(bn / 3); i++) {
                tr[i] = new TableRow(this);
            }
        } else {
            TableRow[] tr = new TableRow[(bn / 3) + 1];
            for (int i = 1; i <=(bn / 3) + 1; i++) {
                tr[i] = new TableRow(this);
            }
        }

通过：

int bn = 9;
TableRow[] tr = null;
        if (bn % 3 == 0) {
            tr = new TableRow[bn / 3];
            for (int i = 1; i <=(bn / 3); i++) {
                tr[i] = new TableRow(this);
            }
        } else {
            tr = new TableRow[(bn / 3) + 1];
            for (int i = 1; i <=(bn / 3) + 1; i++) {
                tr[i] = new TableRow(this);
            }
        }

用于在TableRow中循环三个按钮的算法

1 个答案: